15.3.53 Sketch the region of the double integration and evaluate

In summary, to graph this in Desmos, click on the "wrench" icon and select the polar coordinate grid. It is not possible to graph $\theta=\pi/6$ since it is not a function of $r$. The integral is from $0$ to $\pi/6$ and has a solution of $W|A=\frac{5}{3\sqrt{3}}$.
  • #1
karush
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$\textsf{a. Sketch the region of integration and evaluate.}\\$
\begin{align*}\displaystyle
\int_{6}^{\frac{\pi}{6}}
\int_{0}^{\sec{\theta}}
6r^{3} drd\theta\\
W|A=\frac{5}{3\sqrt{3}}
\end{align*}
OK I really didn't know how to do this in desmos
 
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  • #2
So your question is just about how to graph this using "Desmos"? First, to get to polar coordinates, click on the "wrench" icon in the upper right of the page, just below the menu bar. That opens a dialog box that has "Grid", "Axis Numbers", "X-Axis", and "Y-Axis" checked. Right below "Grid" are two circles, one with a rectangular pattern, the other with radii and circles. Click on the second to get a polar coordinate grid. There is no way to graph [tex]\theta= \pi/6[/tex] in Desmos since all function have to be functions of r but it is easy to see that it is a radial line.

Is the integral really from 6 to [tex]\pi/6[/tex]? Are you sure it is not from 0 to [tex]\pi/6[/tex]? That would make much more sense.
 
  • #3
karush said:
$\textsf{a. Sketch the region of integration and evaluate.}\\$
\begin{align*}\displaystyle
\int_{0}^{\frac{\pi}{6}}
\int_{0}^{\sec{\theta}}
6r^{3} drd\theta\\
W|A=\frac{5}{3\sqrt{3}}
\end{align*}
OK I really didn't know how to do this in desmos

yes sorry it should be $\displaystyle\int_{0}^{\frac{\pi}{6}}$
 

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FAQ: 15.3.53 Sketch the region of the double integration and evaluate

What is the purpose of sketching the region for double integration?

The sketch of the region for double integration is used to visually represent the area or volume that needs to be calculated. This helps to better understand the boundaries and limits of the integration and makes the evaluation process easier.

How is the region for double integration determined?

The region for double integration is determined by the given limits of integration for both variables. These limits define the boundaries of the integration and the shape of the region, which can be rectangular, triangular, circular, or any other shape.

What is the difference between single and double integration?

Single integration is used to find the area under a curve or the volume of a solid, while double integration is used to find the volume of a solid in three-dimensional space or the area of a region in two-dimensional space.

Can the region for double integration be irregular?

Yes, the region for double integration can be irregular in shape. In such cases, it is important to properly define the limits of integration to accurately evaluate the integral.

How is the evaluation of double integration done after sketching the region?

After sketching the region, the integral is evaluated by integrating with respect to one variable first and then the other. The limits of integration are substituted into the integral, and the resulting expression is then solved using basic algebraic techniques.

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