15.3 Express an integral for finding the area of region bounded by:

In summary: Re: 15.3 Express and integral for finding the area of region bounded by:Yes. First, since we are simply finding the area $A$ bounded by $R$, the integrand will be 1. Using vertical strips, and the work already provided by skeeter, we could write:A=\int_0^3\int_{x-2}^{2\sqrt{x}}\,dy\,dx+\int_3^{4+2\sqrt{3}}\int_{\frac{x}{3}}^{2\sqrt{x}}\,dy\,dxCan you write the intergrals using horizontal strips?The integral can
  • #1
karush
Gold Member
MHB
3,269
5
ok so there are 3 peices to this
Express and integral for finding the area of region bounded by:

\begin{align*}\displaystyle
y&=2\sqrt{x}\\
3y&=x\\
y&=x-2
\end{align*}

View attachment 7250
 

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  • #2
Re: 15.3 Express and integral for finding the area of region bounded by:

karush said:
ok so there are 3 peices to this
Express and integral for finding the area of region bounded by:

\begin{align*}\displaystyle
y&=2\sqrt{x}\\
3y&=x\\
y&=x-2
\end{align*}

http://mathhelpboards.com/attachments/calculus-10/7250-15-3-express-integral-finding-area-region-bounded-15-3-png

$3y=x \implies y = \dfrac{x}{3}$

first intersection ...

$x-2 = \dfrac{x}{3} \implies x = 3$

second intersection ...

$x-2 = 2\sqrt{x} \implies x=4+2\sqrt{3}$
$\displaystyle A = \int_0^3 2\sqrt{x} - \dfrac{x}{3} \, dx + \int_3^{4+2\sqrt{3}} 2\sqrt{x} - (x-2) \, dx$
 
  • #3
Re: 15.3 Express and integral for finding the area of region bounded by:

i was courious if this could be iterated into a double integral
 
  • #4
Re: 15.3 Express and integral for finding the area of region bounded by:

karush said:
i was courious if this could be iterated into a double integral

Yes. First, since we are simply finding the area $A$ bounded by $R$, the integrand will be 1. Using vertical strips, and the work already provided by skeeter, we could write:

\(\displaystyle A=\int_0^3\int_{x-2}^{2\sqrt{x}}\,dy\,dx+\int_3^{4+2\sqrt{3}}\int_{\frac{x}{3}}^{2\sqrt{x}}\,dy\,dx\)

Can you write the intergrals using horizontal strips?
 
  • #5
Re: 15.3 Express and integral for finding the area of region bounded by:

MarkFL said:
Yes. First, since we are simply finding the area $A$ bounded by $R$, the integrand will be 1. Using vertical strips, and the work already provided by skeeter, we could write:

\(\displaystyle A=\int_0^3\int_{x-2}^{2\sqrt{x}}\,dy\,dx+\int_3^{4+2\sqrt{3}}\int_{\frac{x}{3}}^{2\sqrt{x}}\,dy\,dx\)

Can you write the intergrals using horizontal strips?

but isn't this still 2 integral sets just added together ??
 
  • #6
Re: 15.3 Express and integral for finding the area of region bounded by:

karush said:
but isn't this still 2 integral sets just added together ??

Yes, but given the nature of the bounded region, there is no way I know of to express it as a single integral without a translation and conversion to polar coordinates.

We could translate everything down 1 unit and 3 units to the left:

View attachment 7265

Can you determine the limits in polar coordinates?
 

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FAQ: 15.3 Express an integral for finding the area of region bounded by:

What is an integral?

An integral is a mathematical concept that represents the area under a curve or the accumulation of a quantity over an interval. It can also be thought of as the inverse operation of differentiation.

How do you express an integral?

An integral is expressed using the notation ∫f(x)dx, where f(x) is the function being integrated and dx is the variable of integration. The integral symbol, ∫, represents the sum of infinite small rectangles under the curve of the function.

What is the purpose of finding the area of a region bounded by a curve?

The area of a region bounded by a curve is often used in mathematics and science to solve real-world problems. It can also be used to find the volume of a solid or the length of a curve, among other applications.

How do you find the area of a region bounded by a curve using an integral?

To find the area of a region bounded by a curve, you need to express the integral as ∫f(x)dx and evaluate it over the given interval. This will give you the value of the area under the curve within that interval.

What are some common examples of using integrals to find the area of a region?

Some common examples include finding the area under a velocity-time graph to determine displacement, calculating the area under a force-distance graph to find the work done, and determining the area of a cross-section to find the volume of a solid.

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