2as = v^2 an other equations dealing with the past

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In summary: They just don't give the full picture and can only be used in certain scenarios.In summary, the conversation discusses the use of the formula 2as = v^2-vo^2 in basic physics classes and the lack of mention of its inaccuracy. It is argued that Newton's physics is sufficient for most real world problems and it is not practical to calculate relativistic movement. However, the formula is still used because it is correct within its applicable domain and is supported by experimental evidence. It is also mentioned that the suvat equations are correct in relativity but can only be used in certain scenarios.
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spino
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2as = v^2 but why do they have the formula 2as = v^2-vo^2 displayed as correct without a reference that its wrong. In Basic physics classes it may not even be mentioned that its wrong. I understand that no one is teaching relativistic physics but why not even mention it. Its been over a 100 years and its still being used in physics books today as being correct along with other formulae dealing with the past.
 
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https://chem.tufts.edu/answersinscience/relativityofwrong.htm
 
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What is your question? Newton's physics is good enough to cover most of all real world problems. As it is easier, it doesn't make sense to calculate the movement of a car relativistic. It's not measurable.
spino said:
but why not even mention it
It will be mentioned where it is relevant.

If you meant the difference of the term ##v_0##, then this is the difference whether there is an initial velocity before acceleration starts or not. Both are valid for certain cases.
 
  • #4
spino said:
its still being used in physics books today as being correct along with other formulae dealing with the past.
It is still being used because it is still correct within its domain of applicability, as shown by a mountain of experimental evidence.

Edit: actually, the suvat equations are exactly correct, even in relativity.
 
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FAQ: 2as = v^2 an other equations dealing with the past

What is the meaning of the equation 2as = v^2?

The equation 2as = v^2 represents the relationship between an object's acceleration (a), displacement (s), and initial velocity (v) in a linear motion scenario. It is also known as the kinematic equation for constant acceleration.

How do you use the 2as = v^2 equation to solve for a specific variable?

In order to solve for a specific variable in the 2as = v^2 equation, you need to rearrange the equation to isolate the desired variable. For example, if you want to solve for acceleration (a), you would divide both sides by 2s and take the square root of both sides.

What is the significance of the number 2 in the 2as = v^2 equation?

The number 2 in the 2as = v^2 equation represents the fact that an object's velocity increases or decreases by a factor of 2 when its acceleration and displacement are doubled or halved, respectively.

How does the 2as = v^2 equation apply to real-life scenarios?

The 2as = v^2 equation can be applied to real-life scenarios involving linear motion, such as a car accelerating from rest or a ball being thrown into the air. It helps us understand how an object's velocity changes over time when it is subjected to a constant acceleration.

Are there any other equations that deal with the past besides 2as = v^2?

Yes, there are other equations that deal with the past and relate to an object's motion. Some examples include the displacement equation (s = ut + 1/2at^2), the velocity equation (v = u + at), and the final velocity equation (v^2 = u^2 + 2as). These equations can also be used to analyze an object's past motion and predict its future behavior.

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