2D Kinematics - Projectile Motion Question

Then use that time and the initial y component of velocity to find the maximum height using the equation y = voyt + 1/2at^2. In summary, by using the given values for the angle, initial speed, and distance from the cannon, we can calculate the time of flight and use it to find the maximum height above the cannon's mouth where the net should be placed in order to catch the daredevil.
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Homework Statement



A daredevil is shot out of a cannon at 33.7◦ to the horizontal with an initial speed of 25.5 m/s. A net is positioned at a horizontal distance of 43.7 m from the cannon from which the daredevil is shot.
The acceleration of gravity is 9.81 m/s^2
At what height above the cannon’s mouth should the net be placed in order to catch the daredevil?
Answer in units of m

Given: θ = 33.7; vo = 25.5 m/s; dx = 43.7m; a = 9.81m/s^2
Find: dy

Homework Equations



vox = vo(cosθ)
voy = vo(sinθ)

[I'm stuck on what other equations I can use]


The Attempt at a Solution



I first drew a diagram with no problem.
vox = (25.5m/s)cos33.7 = 21.1m/s @ a = 0m/s^2
voy = (25.5m/2)sin33.7 = 14.1m/s @ a = -9.81m/s^2

So we now know initial velocity in the x direction is 21.1m/s, and initial velocity in the y direction is 14.1m/s. I am a little confused on where to go from here.
 
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  • #2
You know how far the shot goes in the x direction (43.7 m) and the initial x component of velocity, so you can calculate the time of flight.
 

Related to 2D Kinematics - Projectile Motion Question

1. What is 2D Kinematics and Projectile Motion?

2D Kinematics refers to the study of motion in two dimensions, typically represented on a coordinate plane. Projectile motion is a specific type of 2D motion in which an object is launched at an angle and follows a curved path due to the influence of gravity.

2. What are the key equations used to solve 2D projectile motion problems?

The key equations used to solve 2D projectile motion problems include the equations for horizontal and vertical displacement, velocity, and acceleration, which are derived from the principles of kinematics and the laws of motion.

3. How does the angle of launch affect the trajectory of a projectile?

The angle of launch has a significant impact on the trajectory of a projectile. The steeper the angle, the higher the projectile will travel and the shorter the horizontal distance it will cover. On the other hand, a shallower angle will result in a lower trajectory and a longer horizontal distance.

4. What is the relationship between the horizontal and vertical components of a projectile's velocity?

The horizontal and vertical components of a projectile's velocity are independent of each other. This means that the horizontal velocity remains constant throughout the motion, while the vertical velocity is affected by gravity and will change over time.

5. How can we determine the maximum height and range of a projectile?

The maximum height and range of a projectile can be determined by using the equations for vertical velocity and displacement. The maximum height will occur at the peak of the trajectory when the vertical velocity is zero, and the range can be calculated by finding the horizontal displacement at the time the projectile returns to the same height as the initial launch point.

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