3.4.238 AP calculus exam Limits with ln

In summary, the given limit expression is $\displaystyle\lim_{h\to 0}\dfrac{\ln{(4+h)}-\ln{h}}{h}$ and the options are (A) 0, (B) $\dfrac{1}{4}$, (C) 1, (D) $e$, and (E) DNE. After checking the limit definition of a derivative, it is determined that the limit diverges, making the answer (E) DNE.
  • #1
karush
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Solve
$$\displaystyle\lim_{h\to 0}
\dfrac{\ln{(4+h)}-\ln{h}}{h}$$
$$(A)\,0\quad
(B)\, \dfrac{1}{4}\quad
(C)\, 1\quad
(D)\, e\quad
(E)\, DNE$$
The Limit diverges so the Limit Does Not Exist (E)ok the only way I saw that it diverges is by plotting
not sure what the rule is that observation would make ploting not needed

also I noticed these AP sample questions are getting a lot of views so thot I would continue to post more
 
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  • #2
Check your limit expression again. Should be

$\displaystyle \lim_{h \to 0} \dfrac{\ln(4+h) - \color{red}{ \ln(4)}}{h}$
Recall the limit definition of a derivative ...

$\displaystyle f’(x) = \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}$

let $x=4$

... try again.
 

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