3 questions about iterated integral

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In summary: Let $E$ be a nonempty Jordan region in $\mathbb{R}^2$ and $f:E \rightarrow [0,\infty)$ be integrable on $E$. Prove that the volume of $\Omega =\left \{ (x,y,z): (x,y) \in E,\;0\leq z\leq f(x,y)) \right \}$ satisfies$Vol(\Omega)=\iint_{E}f\;dA$.
  • #1
i_a_n
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1) Suppose that $f_k$ is integrable on $[a_k,\;b_k]$ for $k=1,...,n$ and set $R=[a_1,\;b_1]\times...\times[a_n,\;b_n]$. Prove that $\int_{R}f_1(x_1)...f_n(x_n)d(x_1,...,x_n)=(\int_{a_1}^{b_1}f_1(x_1)dx_1)...(\int_{a_n}^{b_n}f_n(x_n)dx_n)$2)Compute the value of the improper integral:$I=\int_{\mathbb{R}}e^{-x^2}dx$. How to compute $I \times I$ and use Fubini and the change of variables formula?

3) Let $E$ be a nonempty Jordan region in $\mathbb{R}^2$ and $f:E \rightarrow [0,\infty)$ be integrable on $E$. Prove that the volume of $\Omega =\left \{ (x,y,z): (x,y) \in E,\;0\leq z\leq f(x,y)) \right \}$ satisfies

$Vol(\Omega)=\iint_{E}f\;dA$.Perhaps (2) is the easiest to start with... but I have little idea for (1) and (3)...So thank you for your help.
 
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  • #2
Hello http://www.mathhelpboards.com/members/ianchenmu/,
1) I would use the rule:\(\displaystyle f(x,y)=g(x)h(y)\) where \(\displaystyle R = [a,b]\) x \(\displaystyle [c,d]\) hence:
\(\displaystyle \int\int_R g(x)h(y) dA= \int_a^b g(x)dx\int_c^d h(y) dy\)
cause if we think like this
\(\displaystyle \int\int_R f(x,y)dA = \int_c^d\int_a^b g(x)h(y) dxdy= \int_c^d\left[ \int_a^b g(x)h(y) dx \right]dy\) notice we used Fubini's theorem, notice that \(\displaystyle h(y)\) is a constant and then we can take it out!
I am not really good on explain but I hope you understand.

Regards,
 
  • #3
ianchenmu said:
2)Compute the value of the improper integral:$I=\int_{\mathbb{R}}e^{-x^2}dx$. How to compute $I \times I$ and use Fubini and the change of variables formula?

The standard way is as follows:
$$I^{2}= \int_{ \mathbb{R}}e^{-x^{2}} \,dx \cdot \int_{ \mathbb{R}}e^{-y^{2}} \,dy= \int_{ \mathbb{R}} e^{-(x^{2}+y^{2})} \, dx \, dy.$$
Then change to polar coordinates and see what happens.
 

FAQ: 3 questions about iterated integral

What is an iterated integral?

An iterated integral is a type of integral where the limits of integration are functions of more than one variable. It involves solving multiple integrals in a specific order, with the innermost integral being evaluated first.

Why are iterated integrals useful?

Iterated integrals are useful for solving problems involving multiple variables, such as finding the volume or surface area of 3-dimensional objects or calculating probabilities in statistics. They also allow for more complex integrals to be broken down into simpler, one-dimensional integrals.

What is the difference between a single and an iterated integral?

A single integral involves finding the area under a curve in one dimension, while an iterated integral involves finding the volume or area under a surface in multiple dimensions. In an iterated integral, the limits of integration are functions of more than one variable, while in a single integral, they are constants.

Can an iterated integral be evaluated in any order?

No, the order in which the integrals are evaluated is important as it can affect the final result. The order of integration should be carefully chosen based on the shape of the region being integrated over and the function being integrated.

What are the limits of integration in an iterated integral?

The limits of integration in an iterated integral are determined by the region being integrated over. For a rectangular region, the limits of integration for each variable will be constants. However, for more complex regions, the limits may be functions of the other variables.

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