4.1.310 AP calculus Exam Area under to functions

In summary, the conversation discusses finding the intersection point between two functions, specifically $\ln x$ and $5-x$. The solution involves isolating $x$ and using the calculator to find the approximate value. It is also mentioned that the problem can be solved in different ways depending on whether it is approached in terms of $x$ or $y$.
  • #1
karush
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ok I got stuck real soon...

.a find where the functions meet $$\ln x = 5-x$$
e both sides
$$x=e^{5-x}$$ok how do you isolate x?

W|A returned $x \approx 3.69344135896065...$
but not sure how they got itb.?
c.?
 

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  • #2
FYI, this is a calculator active problem ...

$y = \ln{x} \implies x = e^y$

$y = 5-x \implies x = 5-y$

\(\displaystyle R = \int_0^{1.3065586} (5-y) - e^y \, dy = 2.986\)
 

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  • #3
so then we don't need to know x of the intersection
 
  • #4
karush said:
so then we don't need to know x of the intersection

yes, you need both x and y coordinates of the intersection point ...

(a) can be done w/r to x or y ... I went w/r to y because it only requires a single integral expression

(b) requires x ... two integrals

(c) requires y
 
  • #5
ill go with c
 
  • #6
karush said:
ill go with c

?

(c) is a free response question, not a choice
 

FAQ: 4.1.310 AP calculus Exam Area under to functions

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The purpose of the "4.1.310 AP calculus Exam Area under to functions" is to test a student's understanding and ability to calculate the area under a curve using various methods, such as Riemann sums and integration.

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