What is 4-Vector Potential Transformation under Gauge Fixing?

In summary, a gauge transform involves changing the 4-vector potential while keeping the electric and magnetic fields unchanged. Gauge fixing is the process of selecting conditions on the 4-vector potential to simplify calculations. This is done by adding corresponding terms to the 4-vector potential to make the required condition true. Gauge fixing is useful because the original equations are usually expressed in a gauge-invariant form, meaning they will still hold true regardless of the gauge conditions applied.
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Kulkarni Sourabh
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4- vector potential transformation under Gauge fixing.
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What is 4- vector potential transformation under Gauge fixing ?
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A gauge transform is a change in the 4-vector potential that leaves the ##E## and ##B## fields unchanged. So, for example, consider the 3-vector part of ##A##. Since the ##B## field is the curl of the 3-vector part of ##A##, then changing ##A## by adding a 3-vector with zero curl does not change ##B##.

Gauge fixing means to select particular conditions on ##A## to simplify the calculations you are currently doing. You do this by adding the corresponding things to ##A## such that the required condition is true. There are a number of commonly used gauge fixing conditions.

They are useful because we usually express the original version of the equations in a gauge-invariant (or covariant) form. That means we write all the equations in such a way that they are still true regardless of the gauge conditions we apply. That means if we were to do the calculation in another gauge we would necessarily get the same answer. Assuming, of course, we didn't make a mistake.
 
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FAQ: What is 4-Vector Potential Transformation under Gauge Fixing?

What is a 4-vector potential in the context of electromagnetism?

A 4-vector potential in electromagnetism is a four-dimensional vector that combines the electric potential (scalar potential) and the magnetic vector potential into a single entity. It is denoted as \( A^\mu = ( \phi, \mathbf{A} ) \), where \( \phi \) is the electric potential and \( \mathbf{A} \) is the magnetic vector potential. This formulation is particularly useful in the context of special relativity.

How does the 4-vector potential transform under a Lorentz transformation?

Under a Lorentz transformation, the components of the 4-vector potential transform according to the Lorentz transformation matrix. If \( \Lambda \) represents the Lorentz transformation matrix and \( A^\mu \) is the 4-vector potential, then the transformed 4-vector potential \( A'^\mu \) is given by \( A'^\mu = \Lambda^\mu_{\ \nu} A^\nu \). This ensures that the physical laws remain invariant under changes in inertial reference frames.

Why is the 4-vector potential important in the theory of relativity?

The 4-vector potential is important in the theory of relativity because it provides a covariant formulation of electromagnetism, meaning it respects the principles of special relativity. By combining the electric and magnetic potentials into a single 4-vector, the equations of electromagnetism can be written in a form that is invariant under Lorentz transformations, making them consistent with the theory of relativity.

What is the relationship between the 4-vector potential and the electromagnetic field tensor?

The electromagnetic field tensor \( F^{\mu\nu} \) is derived from the 4-vector potential \( A^\mu \). The components of the field tensor are given by \( F^{\mu\nu} = \partial^\mu A^\nu - \partial^\nu A^\mu \). This tensor encapsulates both the electric and magnetic fields in a covariant form, and it is antisymmetric, meaning \( F^{\mu\nu} = -F^{\nu\mu} \).

How do gauge transformations affect the 4-vector potential?

Gauge transformations change the 4-vector potential without altering the physical electromagnetic fields. A gauge transformation adds the gradient of a scalar function \( \Lambda \) to the 4-vector potential: \( A^\mu \rightarrow A^\mu + \partial^\mu \Lambda \). Despite this change in the potential, the electromagnetic field tensor \( F^{\mu\nu} \) remains unchanged, ensuring that observable quantities like the electric and magnetic fields are unaffected.

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