4x4 matrix that satisfies conditions

In summary, the conversation discusses the conditions and components of a 4x4 matrix, with the goal of finding numerical entries that satisfy the given conditions. The three different conditions described are for three different matrices, with the first one being a basic addition of i and j, the second one being i raised to the power of j-1, and the third one having 1 or -1 entries based on the difference between i and j. The conversation also mentions the use of the physicsforums.com android app for posting questions and the proper way to show gratitude for help.
  • #1
burton95
54
0
A = [aij]

1) aij = i +j
2) aij = i^j-1
3) aij = 1 if |i - j| >1
-1 if |i - j| _< 1

I don't even know where to begin. Are i and j compenents of the matrix? Please help me get started
 
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  • #2
i and j and indices of the components. I would guess they take the values 1,2,3,4. So 1) would say a11=1+1=2, a12=1+2=3. Etc. Just write out the whole matrix in each case.
 
  • #3
Mod note: I removed the copied text that Dick refers to, below.
The three different conditions 1), 2) and 3) describe different matrices. Which one are you doing? And judging by the title, it's supposed to be 4x4.
 
Last edited by a moderator:
  • #4
Dick said:
The three different conditions 1), 2) and 3) describe different matrices. Which one are you doing? And judging by the title, it's supposed to be 4x4.
Oops, you're right. The first 4x4 should go like...

[tex]A_{i,j} =
\begin{pmatrix}
a_{1+1} & a_{1+2} & \cdots & a_{1+j} \\
a_{2+1} & a_{2+2} & \cdots & a_{2+j} \\
\vdots & \vdots & \ddots & \vdots \\
a_{i+1} & a_{i+2} & \cdots & a_{i+j}\\
\end{pmatrix}[/tex]
 
  • #5
phion said:
Oops, you're right. The first 4x4 should go like...

[tex]A_{i,j} =
\begin{pmatrix}
a_{1+1} & a_{1+2} & \cdots & a_{1+j} \\
a_{2+1} & a_{2+2} & \cdots & a_{2+j} \\
\vdots & \vdots & \ddots & \vdots \\
a_{i+1} & a_{i+2} & \cdots & a_{i+j}\\
\end{pmatrix}[/tex]

I admire your texing skills but that's pretty strange looking as an answer to the question. The matrix will have numerical entries. And besides, the goal here is not even to give answers. It's to show the poster how to solve it.
 
  • #6
Dick said:
I admire your texing skills but that's pretty strange looking as an answer to the question. The matrix will have numerical entries. And besides, the goal here is not even to give answers. It's to show the poster how to solve it.
I'm aware how the answer should look, and thank you for the compliment. I'm still trying to learn LaTeX, so I thought this would be an ample opportunity. I am only trying to help. :smile:
 
  • #7
Thanks. I was trying to come up with one matrix to satisfy all the conditions mentioned. Upon review its states "condition". Wheeewh
 
  • #8
so I got these as my matrices

1)
2 3 4 5
3 4 5 6
4 5 6 7
5 6 7 8

2)
1 1 1 1
1 2 4 8
1 3 9 27
1 4 16 64

3)
-1 -1 -1 -1
-1 -1 -1 -1
1 -1 -1 -1
1 1 -1 -1

yes, no?
 
  • #9
burton95 said:
so I got these as my matrices

1)
2 3 4 5
3 4 5 6
4 5 6 7
5 6 7 8

2)
1 1 1 1
1 2 4 8
1 3 9 27
1 4 16 64

3)
-1 -1 -1 -1
-1 -1 -1 -1
1 -1 -1 -1
1 1 -1 -1

yes, no?

The first one looks ok. The second one is ok if the formula is i^(j-1). I'd read i^j-1 as (i^j)-1. For 3) shouldn't there be some ones in the upper right corner too?
 
  • #10
you're correct on the 3rd matrix. The notation for 2) is aij = ij-1. I use the physicsforums.com android app and when I post using the app there is no template. Does this mean that using the app to post questions isn't legitimate? Also is there a way to keep score where I can thank folks for the help?

thanks
 
Last edited:
  • #11
burton95 said:
you're correct on the 3rd matrix. The notation for 2) is aij = ij-1. I use the physicsforums.com android app and when I post using the app there is no template. Does this mean that using the app to post questions isn't legitimate? Also is there a way to keep score where I can thank folks for the help?

thanks

It's odd the android app doesn't give you a template. But posting questions anyway you like is legit. Just show how you attempted to solve it before asking for help. And a simple thanks is fine. And you just did that. You are welcome!
 

FAQ: 4x4 matrix that satisfies conditions

What is a 4x4 matrix?

A 4x4 matrix is a rectangular array of numbers or variables arranged in 4 rows and 4 columns. It is commonly used in linear algebra and computer graphics to represent transformations and equations.

What conditions must a 4x4 matrix satisfy?

A 4x4 matrix must satisfy certain conditions in order to be considered valid. These conditions include having 4 rows and 4 columns, having the same number of elements in each row and column, and having elements that can be added, subtracted, and multiplied together.

How do you determine if a 4x4 matrix satisfies the conditions?

To determine if a 4x4 matrix satisfies the conditions, you can check its dimensions to ensure it is 4 rows by 4 columns. Then, you can check if each row and column has the same number of elements. Finally, you can perform basic operations on the elements to ensure they are valid.

What are some examples of valid 4x4 matrices?

Some examples of valid 4x4 matrices include:

  • [1 2 3 4; 5 6 7 8; 9 10 11 12; 13 14 15 16]
  • [0 0 0 0; 0 0 0 0; 0 0 0 0; 0 0 0 0]
  • [2 -3 0 1; 7 4 9 -5; -6 0 8 3; 0 1 0 -2]

What are some examples of invalid 4x4 matrices?

Some examples of invalid 4x4 matrices include:

  • [1 2 3; 4 5 6; 7 8 9]
  • [1 2 3 4; 5 6 7 8; 9 10 11 12; 13 14 15 16; 17 18 19 20]
  • [1 2 3 4; 5 6 7 8; 9 10 11 12; 13 14 15]

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