.5 c train relativity question

In summary, a moving emitter traveling at 0.5c passes point A and emits one photon along the direction of travel. At the same time, a freight train traveling at 0.5c passes point A in the opposite direction. After two seconds, the positions and separations of the emitter, the train, and the photon will depend on the reference frame in which the measurements are made. In some frames, the separations between these bodies may appear to be greater than the speed of light.
  • #1
keepitmoving
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0
a moving emitter passes point A traveling at .5 c and emits one photon along the direction of travel. At that same instant a freight train traveling at .5 c passes point A in the opposite direction.
Question 1 - two seconds later where is the moving emitter with respect to point A?
Question 2 - two seconds later where is the freight train with respect to point A?
Question 3 - where is the photon at that 2 second point with respect to point A?
Question 4 - where is the photon at that 2 second point with respect to the moving emitter?
Question 5 - where is the photon at that 2 second point with respect to the freight train?
Question 6 - how far apart are the freight train and the moving emitter at that 2 second point?
Question 7 - have the photon and the freight train separated at faster than c ?
This isn`t homework, i`m just trying to understand this stuff.
 
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  • #2
keepitmoving said:
a moving emitter passes point A traveling at .5 c and emits one photon along the direction of travel. At that same instant a freight train traveling at .5 c passes point A in the opposite direction.
Question 1 - two seconds later where is the moving emitter with respect to point A?
Question 2 - two seconds later where is the freight train with respect to point A?
I assume "two seconds later" refers to the frame in which each of them are traveling at 0.5c, and where point A is at rest? In this case each of them would be 1 light-second from point A, although of course the answer would be different in other frames.
keepitmoving said:
Question 3 - where is the photon at that 2 second point with respect to point A?
Question 4 - where is the photon at that 2 second point with respect to the moving emitter?
Question 5 - where is the photon at that 2 second point with respect to the freight train?
Again, if you're talking about the frame where both are moving at 0.5c in opposite directions, then the photon is 2 light-seconds away from the point A where it was emitted, which means it's 1 light-second from the emitter and 3 light-seconds from the train.
keepitmoving said:
Question 6 - how far apart are the freight train and the moving emitter at that 2 second point?
2 light-seconds apart.
keepitmoving said:
Question 7 - have the photon and the freight train separated at faster than c ?
In this frame the "closing speed" between them is indeed faster than c, although if you were to switch to the train's own rest frame the photon would be moving away from it at exactly c.
 
  • #3
You continue to ask questions like this, which is good, but you seem to be missing the critical point that observers in different reference frames will disagree on the distance between two bodies and the duration between two events.

keepitmoving said:
Question 1 - two seconds later where is the moving emitter with respect to point A?

There is no absolute answer to the question. It will depend on the reference frame in which the measurement is made, for both "where" and "two seconds later" mean different things to different observers.

In the rest frame of point A ("the embankment"), the answer is 1 light second in the +x direction from A.

In the rest frame of the freight train, the answer is different, for in that frame, A travels at speed 0.5c, but the emitter travels at speed 0.5c + 0.5c = 0.8c, yielding a separation rate of 0.3c. Thus two seconds later, as measured by the freight train, the emitter is 0.6 light-seconds from A.

In other frames, the answer will be still different.


Question 2 - two seconds later where is the freight train with respect to point A?


There is no absolute answer to the question. It will depend on the reference frame in which the measurement is made, for both "where" and "two seconds later" mean different things to different observers.

Question 3 - where is the photon at that 2 second point with respect to point A?

There is no absolute answer to the question. It will depend on the reference frame in which the measurement is made, for both "where" and "two seconds later" mean different things to different observers.

In the rest frame of A, the photon travels at c, so after 2 seconds, the photon is 2 light-seconds from A in the +x direction.

In the rest frame of the emitter, the photon travels at c and A travels backwards at 0.5c. Thus they separate at 1.5c and after 2 seconds the photon is 3 light-seconds from A.

In the rest frame of the train, the photon travels at c and A follows behind it at 0.5c. Thus they separate at 0.5c and after 2 seconds the photon is 1 light-second from A.

In other frames, the answer will be different.

Question 4 - where is the photon at that 2 second point with respect to the moving emitter?

There is no absolute answer to the question. It will depend on the reference frame in which the measurement is made, for both "where" and "two seconds later" mean different things to different observers.

Question 5 - where is the photon at that 2 second point with respect to the freight train?

There is no absolute answer to the question. It will depend on the reference frame in which the measurement is made, for both "where" and "two seconds later" mean different things to different observers.

Question 6 - how far apart are the freight train and the moving emitter at that 2 second point?

There is no absolute answer to the question. It will depend on the reference frame in which the measurement is made, for both "where" and "two seconds later" mean different things to different observers.


Question 7 - have the photon and the freight train separated at faster than c ?

There is no absolute answer to the question. It will depend on the reference frame in which the measurement is made, for both "where" and "two seconds later" mean different things to different observers.

In some frames, the train and photon have separated at more than c. In others, less than c. In still others, c.
 
  • #4
what does rest frame mean?
 
  • #5
yes. i`m referring to the frame where each is moving at .5 c frompoint A
Now, if the photon is at 600km from point A after 2 seconds and the photon is at 300km from the emitter, then the light didn`t move away from the emitter at light speed and this would mean that if the emitter were moving at .9999 c, the light emitted would move away from the emitter at less than .01 c. Is that right?
 
  • #6
keepitmoving said:
yes. i`m referring to the frame where each is moving at .5 c frompoint A
Now, if the photon is at 600km from point A after 2 seconds and the photon is at 300km from the emitter, then the light didn`t move away from the emitter at light speed and this would mean that if the emitter were moving at .9999 c, the light emitted would move away from the emitter at less than .01 c. Is that right?

In the frame you have specified, the light separates from the emitter at that rate, correct. In the rest frame of the emitter (the reference frame in which the emitter is at rest), then that is not correct. In the rest frame of the emitter, the light travels at c and thus separates from the emitter at c. Light travels at c in all reference frames.
 
  • #7
Zik Zak
Did you say that the light separates from the moving emitter (moving relative to point A) at c minus the velocity of the emitter? Or did i state the question right?
 
  • #8
keepitmoving said:
Zik Zak
Did you say that the light separates from the moving emitter (moving relative to point A) at c minus the velocity of the emitter? Or did i state the question right?

Yes, in the frame of the embankment, the photon travels at c and the emitter follows it at 0.5c, so they indeed separate at 0.5c.

Note that this does not mean that they separate at 0.5c in an absolute sense: other observers measure a different rate of separation. In particular the emitter itself observes the separation at a rate of c.
 
  • #9
i`m not familiar with the embankment?
Also, i`ve heard many times that the emitter measures the light moving at c from him (her) but that doesn`t make sense to me if light is moving from A at c as well.
Do i have to just believe or can it make sense to me if i know more?
 
  • #10
keepitmoving said:
Also, i`ve heard many times that the emitter measures the light moving at c from him (her) but that doesn`t make sense to me if light is moving from A at c as well.
Do i have to just believe
No, physics is not about believing, but about measuring and accepting the reproducible results, which are that the same light moves at c for every inertial observer.
keepitmoving said:
or can it make sense to me if i know more?
There is no more to know. You just have to get used to the idea, that "your sense" is based on experience of everyday life, and therefore of limited applicability.
 

FAQ: .5 c train relativity question

What is ".5 c train relativity"?

".5 c train relativity" refers to the concept of time dilation and length contraction that occurs when an object, in this case a train, is moving at a speed of half the speed of light (c). This is a fundamental concept in the theory of relativity proposed by Albert Einstein.

How does ".5 c train relativity" work?

According to the theory of relativity, as an object approaches the speed of light, time slows down for that object. This means that a clock on the moving train would appear to run slower compared to a clock on the stationary ground. Additionally, the length of the train would appear shorter to an observer on the ground due to length contraction.

What is the significance of ".5 c train relativity"?

The concept of ".5 c train relativity" is significant because it challenges our understanding of time and space. It has been proven experimentally and has implications in various fields, such as space travel and GPS technology. It also helps us better understand the nature of the universe.

Can ".5 c train relativity" be observed in everyday life?

Yes, ".5 c train relativity" can be observed in everyday life, although the effects are very small at everyday speeds. For example, the GPS system takes into account time dilation due to the satellites moving at high speeds in space. Additionally, cosmic rays (high-speed particles from space) that constantly bombard Earth also exhibit time dilation effects.

What are the limitations of ".5 c train relativity"?

There are two main limitations of ".5 c train relativity". Firstly, it only applies to objects moving at speeds close to the speed of light. At everyday speeds, the effects are negligible. Secondly, it doesn't take into account the effects of gravity. To fully understand the relationship between time and space, the theory of relativity needs to be combined with the theory of gravity, known as general relativity.

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