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karush
Gold Member
MHB
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7.4.32 Evaluate the integral
$\displaystyle \int_0^1\dfrac{x}{x^2+4x+13}\, dx$
ok side work to complete the square
$x^2+4x=-13$
add 4 to both sides
$x^2+4x+4=-13+4$
simplify
$(x+2)^2+9=0$
ok now whatW|A returned ≈0.03111
$\displaystyle \int_0^1\dfrac{x}{x^2+4x+13}\, dx$
ok side work to complete the square
$x^2+4x=-13$
add 4 to both sides
$x^2+4x+4=-13+4$
simplify
$(x+2)^2+9=0$
ok now whatW|A returned ≈0.03111
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