- #1
Yoran91
- 37
- 0
Hello everyone,
I'm going through Edmond's Angular momentum in quantum mechanics and I found a particular expansion of the 9j symbol in terms of three 6j symbols which I didn't quite understand.
The problem lies in equation 6.4.1 which I simply don't understand.
On page 100/101, (section 6.4), Edmond states that the unitary transformation
[itex]\langle (j_1 j_2) j_{12}, (j_3 j_4) j_{34},jm | (j_1 j_3) j_{13},(j_2 j_4)j_{24},jm \rangle[/itex] can be performed in three steps. In each of these steps the coupling or addition of only three angular momentum operators is carried out.
He states :
[itex]\langle (j_1 j_2) j_{12}, (j_3 j_4) j_{34},jm | (j_1 j_3) j_{13},(j_2 j_4)j_{24},jm \rangle = \\ \Sigma \langle (j_1 j_2)j_{12},j_{34},j | j_1,(j_2 j_{34}) j',j \rangle \\
\times \langle j_2,(j_3 j_4)j_{34},j' | j_3,(j_2 j_4)j_{24},j' \rangle\\
\times \langle j_1,(j_3 j_24)j',j|(j_1 j_3)j_{13},j_{24},j \rangle [/itex].
However, I have no idea how he precisely reduces the addition of four angular momentum operator to three angular momentum operator in these steps. Can anyone explain this?
I'm going through Edmond's Angular momentum in quantum mechanics and I found a particular expansion of the 9j symbol in terms of three 6j symbols which I didn't quite understand.
The problem lies in equation 6.4.1 which I simply don't understand.
On page 100/101, (section 6.4), Edmond states that the unitary transformation
[itex]\langle (j_1 j_2) j_{12}, (j_3 j_4) j_{34},jm | (j_1 j_3) j_{13},(j_2 j_4)j_{24},jm \rangle[/itex] can be performed in three steps. In each of these steps the coupling or addition of only three angular momentum operators is carried out.
He states :
[itex]\langle (j_1 j_2) j_{12}, (j_3 j_4) j_{34},jm | (j_1 j_3) j_{13},(j_2 j_4)j_{24},jm \rangle = \\ \Sigma \langle (j_1 j_2)j_{12},j_{34},j | j_1,(j_2 j_{34}) j',j \rangle \\
\times \langle j_2,(j_3 j_4)j_{34},j' | j_3,(j_2 j_4)j_{24},j' \rangle\\
\times \langle j_1,(j_3 j_24)j',j|(j_1 j_3)j_{13},j_{24},j \rangle [/itex].
However, I have no idea how he precisely reduces the addition of four angular momentum operator to three angular momentum operator in these steps. Can anyone explain this?