|a+b| = |a| + |b| implies a and b parallel?

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Also, ||b||=(|b|)||b||. So, ||a||+||b||=||b||((|c|)+1). Therefore, `|a|` and `|b|` are not parallel in the same direction. In summary, the theorem stating that if |a| + |b| = |a + b|, then |a| and |b| are parallel to each other in the same direction is false. This can be proven by demonstrating a counterexample where |a| and |b| are not parallel in the same direction.
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julypraise
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Is the following theorem true:

Theorem: Suppose [itex]a, \, b \in \mathbb{R}^k[/itex]. If [itex] |a| + |b| = |a + b| [/itex], then [itex] |a| [/itex] and [itex] |b| [/itex] are parallel to each other in the same direction.

I proved the converse, but I couldn't prove the theorem above. Please post the proof or the disproof of it, or a link of them. Thanks.
 
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Hi julypraise! :smile:

The trick to proving this is to calculate the inproduct

[tex]<a+b,a+b>[/tex]

in two different ways. The first way involves

[tex]<a+b,a+b>=|a+b|^2=(|a|+|b|)^2[/tex]

The other way starts as

[tex]<a+b,a+b>=|a|^2+|b|^2+2<a,b>[/tex]

Can you finish it?
 
  • #3
Thank you so much, micromass.

So, by using the trick, I derived that

[itex] 2|a||b| = 2<a, \, b> [/itex], and by the definition of inproduct

[itex] |a||b| = |a||b|cos\theta [/itex]

and therefore, [itex] \theta = 0 [/itex]

where [itex] \theta [/itex] is the angle between.
 
  • #4
julypraise said:
Is the following theorem true:

Theorem: Suppose [itex]a, \, b \in \mathbb{R}^k[/itex]. If [itex] |a| + |b| = |a + b| [/itex], then [itex] |a| [/itex] and [itex] |b| [/itex] are parallel to each other in the same direction.

I proved the converse, but I couldn't prove the theorem above. Please post the proof or the disproof of it, or a link of them. Thanks.

If `a` and `b` are parallel then ∃c∈ℝ s.t., a=cb. So then, ||a+b||=||cb+b||=||b||(|c+1|)≠||a||+||b||. Since ||a||=||cb||=(|c|)||b||.
 
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  • #5


I cannot provide a proof or disproof of this theorem without further context and information about the definitions and assumptions being used. In mathematics, it is important to clearly define the terms and assumptions being made before trying to prove or disprove a statement. Additionally, it is important to consider counterexamples and exceptions to the statement in question.

Without any further context, it is not possible for me to provide a definitive answer. However, I can offer some thoughts and considerations that may be helpful in approaching this problem.

First, let's define what it means for two vectors to be parallel. Two vectors are considered parallel if they have the same direction or are in opposite directions. This means that they lie on the same line or on parallel lines. In other words, if we have two vectors a and b, they are parallel if there exists a scalar c such that a = cb.

Now, let's consider the statement |a| + |b| = |a + b|. This statement can be rewritten as |a| + |-b| = |a + b|. We can then use the definition of absolute value to rewrite this as |a| + |b| = |-a| + |b|. This means that the magnitudes of a and -a are equal, and the same goes for the magnitudes of b and -b. This suggests that a and -a, as well as b and -b, are parallel to each other. However, this does not necessarily imply that a and b are parallel to each other.

Furthermore, we can consider counterexamples to this statement. For example, let a = <1, 0, 0> and b = <0, 1, 0>. These vectors have the same magnitude but are not parallel to each other. Additionally, let a = <1, 0, 0> and b = <1, 1, 0>. These vectors have different magnitudes but are parallel to each other.

In conclusion, I cannot provide a proof or disproof of this theorem without further context and information. It is important to carefully define the terms and assumptions being made, and to consider counterexamples and exceptions to the statement in question.
 

FAQ: |a+b| = |a| + |b| implies a and b parallel?

What is the definition of parallel lines?

The definition of parallel lines is two lines that are always the same distance apart and never intersect.

How can we prove that a and b are parallel if |a+b| = |a| + |b|?

We can prove that a and b are parallel by using the triangle inequality theorem. If |a+b| = |a| + |b|, then the sum of the lengths of any two sides of a triangle must be greater than the length of the third side. This means that the two sides, a and b, are parallel to each other.

Can the equation |a+b| = |a| + |b| hold true for non-parallel lines?

No, the equation |a+b| = |a| + |b| can only hold true for parallel lines. This is because, in non-parallel lines, the triangle inequality theorem does not hold, and the sum of the lengths of any two sides of a triangle can be equal to or less than the length of the third side.

Are there any other conditions besides |a+b| = |a| + |b| that prove a and b are parallel?

Yes, there are other conditions that can prove a and b are parallel. For example, if the slopes of two lines are equal, or if the lines have the same y-intercept, they are parallel. Additionally, if the lines are perpendicular to the same line, they are also parallel.

How does the equation |a+b| = |a| + |b| relate to the distance between parallel lines?

The equation |a+b| = |a| + |b| is directly related to the distance between parallel lines. It states that the sum of the lengths of any two segments on parallel lines is equal to the sum of the lengths of those segments on the same line. This means that the distance between two parallel lines is the same at any point along the lines.

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