A,B similar <=> Rank(A) = Rank(B)?

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The discussion explores the relationship between matrix similarity and rank, specifically questioning if "A and B are similar" implies "Rank(A) = Rank(B)." It is established that while the implication "Rank(A) = Rank(B) => A is similar to B" is always true, the reverse is not necessarily valid. A counter-example is provided using the identity matrix and a scalar multiple of it, demonstrating that two matrices can have the same rank without being similar. The conclusion drawn is that similarity does not equate to equal rank, confirming the non-equivalence of the two statements.
nonequilibrium
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So I was wondering if "A and B are similar" is equivalent to "Rank(A) = Rank(B)".

So obviously "=>" is always true, but I can't find any information on "<=". It seems logical, but I can't find a way to prove it. Also, even finding a counter-example doesn't seem easy, because then you'd have to prove there isn't any invertible matrix P so that P^{-1} A P = B, so I suppose a counter-example should be done with reductio ad absurdum, but nothing strikes me as an obvious example.

Any help?

Thank you,
mr. vodka
 
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What matrices are similar to the identity matrix?
 
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Actually I'm not sure?

But it gave me the idea that if a matrix is similar to the identity matrix, it has the same determinant, thus 1. Yet there are non-singular matrices with determinants not equal to one, thus giving me a reduction ad absurdum :) thus it's not an equivalency.

Thank you.
 
Let A = I and B = λ I, so r(A) = r (B). Can A and B be similar?
 
False even in the 1x1 case.
 
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