A baseball is thrown straight up with initial speed

In summary, when a baseball is thrown straight up with initial speed v(o) and air resistance is taken into account, the ball will have less speed when it returns to its initial height. This is due to the fact that the projectile has the same initial kinetic energy regardless of the angle of projection, but the presence of air resistance causes the velocity in the x-direction to decrease, resulting in a lower overall speed when the ball reaches its initial height. Additionally, the x-coordinate will remain the same when the ball is thrown straight up.
  • #1
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A baseball is thrown straight up with initial speed v(o). If air resistance cannot be ignored, when the ball returns to its initial height its speed is less than v(o). Explain why, using energy concepts.
I am very confused as to why this is.

A projectile has the same initial kinetic energy no matter what the angle of projection. Why doesn't it rise to the same maximum height in each case?

Is it because the velocity in the x-direction is different?
 
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  • #2
If air resistance cannot be ignored,

What happens when the ball travels through the air?¨
Also, if the ball is thrown straight up the x-coordidate will not change.
 
  • #3


I can explain the phenomenon you described using energy concepts. When a baseball is thrown straight up with an initial speed v(o), it has both kinetic energy and potential energy. As it rises, the kinetic energy is converted into potential energy due to the force of gravity acting on it. However, when air resistance is present, it acts as a dissipative force and reduces the kinetic energy of the ball as it rises. This means that the ball does not have enough kinetic energy to reach the same maximum height it would have without air resistance.

In terms of energy conservation, the total energy of the ball (kinetic energy + potential energy) remains the same throughout its trajectory. However, the energy is redistributed as the ball moves against the force of air resistance. This is why the ball returns to its initial height with a lower speed than v(o).

Furthermore, the angle of projection does not affect the maximum height reached by the ball. This is because the only force acting on the ball is gravity, which is independent of the angle of projection. However, the velocity in the x-direction does affect the trajectory of the ball and the time it takes to reach its maximum height. This is because the velocity in the x-direction determines the horizontal displacement of the ball, while the vertical displacement is determined by the force of gravity.

In summary, air resistance plays a crucial role in the trajectory and speed of a projectile. It acts as a dissipative force and reduces the kinetic energy of the ball, resulting in a lower speed when it returns to its initial height. This phenomenon can be explained using the principles of energy conservation.
 

FAQ: A baseball is thrown straight up with initial speed

What is the initial speed of the baseball?

The initial speed of the baseball refers to the velocity at which it is thrown straight up. It can be calculated using the equation v0 = v - gt, where v0 is the initial velocity, v is the final velocity (which in this case is 0 since the ball reaches its maximum height and then falls back down), g is the acceleration due to gravity (9.8 m/s^2), and t is the time in seconds.

How high does the baseball go?

The maximum height that the baseball reaches can be calculated using the equation h = v0^2 / 2g, where h is the maximum height, v0 is the initial velocity, and g is the acceleration due to gravity. This calculation assumes that there is no air resistance.

What is the acceleration of the baseball?

The acceleration of the baseball is constant and is equal to the acceleration due to gravity, which is 9.8 m/s^2. This means that the ball will accelerate towards the ground at a rate of 9.8 meters per second squared.

How long does it take for the baseball to reach its maximum height?

The time it takes for the baseball to reach its maximum height can be calculated using the equation t = v0 / g, where t is the time, v0 is the initial velocity, and g is the acceleration due to gravity. This calculation assumes that there is no air resistance.

What happens to the baseball after it reaches its maximum height?

After reaching its maximum height, the baseball will begin to fall back down towards the ground due to the force of gravity. Its velocity will increase until it reaches the same speed it was thrown with, but in the opposite direction. It will then continue to fall until it reaches the ground, assuming there is no air resistance.

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