A bucket of mass 1.60 kg is whirled in a vertical circle of radius 1.00 m.

In summary, the conversation discussed calculating the speed of a bucket whirled in a vertical circle of radius 1.00 m, with a mass of 1.60 kg and a tension of 25.0 N at the bottom. The solution for part (a) was found to be 2.42 m/s. For part (b), Newton's 2nd law was applied to solve for the required speed at the top of the circle so that the rope does not go slack. The equation was set up and solved, resulting in a speed of 3.13 m/s.
  • #1
fineztpaki
13
0

Homework Statement


A bucket of mass 1.60 kg is whirled in a vertical circle of radius 1.00 m. At the lowest point of its motion the tension in the rope supporting the bucket is 25.0 N.
(a) Find the speed of the bucket.
(b) How fast must the bucket move at the top of the circle so that the rope does not go slack?

The Attempt at a Solution


I figured out A, the speed of the bucket to be 2.42 m/s but i don't understand how to find B.. can someone help please?
 
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  • #2
When the rope just goes slack what happens to its tension?
 
  • #3
the tension decreases?
 
  • #4
fineztpaki said:
the tension decreases?
To what value?
 
  • #5
less than 25?
 
  • #6
Is there any formula i would be able to use to solve this?
 
  • #7
If there's any tension in the rope, it's not slack. The only formula you need is Newton's 2nd law.
 
  • #8
How do I get speed, or velocity (m/s) from that?
The answer is supposed to be in m/s ... I'm still confused
 
  • #9
You solve part (b) the same basic way you solved part (a). What forces act on the bucket? Apply Newton's 2nd law. The differences: The bucket is at the top instead of the bottom. (What does that change?) And the tension is different. (What must it be just as the rope goes slack?)

Once you set up your equation you solve for v just like you did in part (a).
 
  • #10
3.13
 
  • #11
alright got it! thanks!
 
  • #12
fineztpaki said:
3.13
Yep. In m/s.
 

FAQ: A bucket of mass 1.60 kg is whirled in a vertical circle of radius 1.00 m.

What is the centripetal force acting on the bucket?

The centripetal force acting on the bucket can be calculated using the formula F = mv^2/r, where m is the mass of the bucket, v is the velocity, and r is the radius of the circle.

What is the minimum speed required to keep the bucket moving in a vertical circle?

The minimum speed required to keep the bucket moving in a vertical circle is the speed at the top of the circle, which can be calculated using the formula v = √(gr), where g is the acceleration due to gravity and r is the radius of the circle.

What happens to the tension in the rope as the bucket moves through the circle?

The tension in the rope changes as the bucket moves through the circle. At the bottom of the circle, the tension is equal to the weight of the bucket plus the centripetal force. At the top of the circle, the tension is equal to the weight of the bucket minus the centripetal force.

What is the direction of the acceleration of the bucket?

The direction of the acceleration of the bucket is always towards the center of the circle, also known as the centripetal direction. This is because the acceleration is caused by the centripetal force, which is directed towards the center of the circle.

What happens if the speed of the bucket is too low?

If the speed of the bucket is too low, it will not be able to complete the vertical circle and will instead fall to the ground. This is because the centripetal force is not strong enough to overcome the force of gravity.

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