- #1
muskaanhamad
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- Homework Statement
- A critically damped simple harmonic oscillator starts from an amplitude of 5.0 cm and comes to rest at equilibrium 3.5 sec later. The simple harmonic oscillator is made of a .58 kg mass hanging from a spring with spring constant 150 N/m. Assuming the friction force is in the vertical direction, how big is the friction force?
- Relevant Equations
- Critically Damping factor c = 2√(km)
Friction force = -cv
Velocity v=disp/time
c = Critically Damped factor
c = 2√(km)
c = 2 × √(150 × .58) = 18.65
Friction force = -cv
Velocity v = disp/time = .05/3.5
Friction force = - 18.65 * .05/3.5 = -.27 N
I am not sure if above is correct. Please check and let me know how to do it.
c = 2√(km)
c = 2 × √(150 × .58) = 18.65
Friction force = -cv
Velocity v = disp/time = .05/3.5
Friction force = - 18.65 * .05/3.5 = -.27 N
I am not sure if above is correct. Please check and let me know how to do it.