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redglasses
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Hi everyone, first time poster, long time reader (only because you're all so clever and I feel my contribution wouldn't be all that helpful haha).
A dielectric (homogeneous, isotropic, with relative permativity [tex]\epsilon_{r}[/tex]) is located in the region x<0.
An infinite line of charge [tex]\lambda[/tex], parallel to surface of dielectric slab and parallel to z axis, is located at (x,y,z) = (d,0,0). x>0 is a vacuum.
We are told that the field in the region x>0 can be found by way of the method of images, by introducing an image charge [tex]\lambda^{'}[/tex], at (-d,0,0); and the field in the region x<0 can be found by replacing [tex]\lambda[/tex] with [tex]\lambda^{''}[/tex].
E = -[tex]\nabla[/tex]V
Surface charge: [tex]\sigma[/tex] = [tex]\epsilon_{0}[/tex]*E [tex]\cdot[/tex] [tex]\widehat{n}[/tex]
This problem is confusing me. Up until now it was my understanding that I could only really use the method of images when at the boundary the potential is equal to zero. That being said I did see an example in class where the potential was constant, but I found this rather confusing.
What I tried to do for the first part of the question, more as a thought process than by way of calculation (as for some reason I keep getting stuck finding the potential as I'm far more used to working more in 2 dimensions with image charges instead of lines of charge for this kind of problem) is to try to set up a similar problem where at the boundary it is an infinite grounded conducting plane (ie V = 0), try to find the surface charge that would be induced by [tex]\lambda[/tex] and integrating to find [tex]\lambda^{'}[/tex] and showing they're equivalent.
But by my luck that's probably the completely wrong approach! I have a feeling I've misunderstood a crucial concept.
I understand this is a poor attempt at a solution - I have almost resigned myself to the fact that I won't nut out this question without seeing my lecturer, but any small pushes in the right direction would be gladly accepted and greatly appreciated!
Homework Statement
A dielectric (homogeneous, isotropic, with relative permativity [tex]\epsilon_{r}[/tex]) is located in the region x<0.
An infinite line of charge [tex]\lambda[/tex], parallel to surface of dielectric slab and parallel to z axis, is located at (x,y,z) = (d,0,0). x>0 is a vacuum.
We are told that the field in the region x>0 can be found by way of the method of images, by introducing an image charge [tex]\lambda^{'}[/tex], at (-d,0,0); and the field in the region x<0 can be found by replacing [tex]\lambda[/tex] with [tex]\lambda^{''}[/tex].
Homework Equations
E = -[tex]\nabla[/tex]V
Surface charge: [tex]\sigma[/tex] = [tex]\epsilon_{0}[/tex]*E [tex]\cdot[/tex] [tex]\widehat{n}[/tex]
The Attempt at a Solution
This problem is confusing me. Up until now it was my understanding that I could only really use the method of images when at the boundary the potential is equal to zero. That being said I did see an example in class where the potential was constant, but I found this rather confusing.
What I tried to do for the first part of the question, more as a thought process than by way of calculation (as for some reason I keep getting stuck finding the potential as I'm far more used to working more in 2 dimensions with image charges instead of lines of charge for this kind of problem) is to try to set up a similar problem where at the boundary it is an infinite grounded conducting plane (ie V = 0), try to find the surface charge that would be induced by [tex]\lambda[/tex] and integrating to find [tex]\lambda^{'}[/tex] and showing they're equivalent.
But by my luck that's probably the completely wrong approach! I have a feeling I've misunderstood a crucial concept.
I understand this is a poor attempt at a solution - I have almost resigned myself to the fact that I won't nut out this question without seeing my lecturer, but any small pushes in the right direction would be gladly accepted and greatly appreciated!
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