A little question about c language

[nenyan]

#include <stdio.h>
#include <stdlib.h>
int main()
{ double a[10];
int i=0;
for(i=0;i<10;i++)
a=0.0;
for(i=0;i<10;i++)
printf("a[%d]=%e, "), i, a;}

The result is radom number. What's wrong with my code?

 

[D H]

The result is radom number. What's wrong with my code?

The problem is here:

printf("a[%d]=%e, "), i, a;

Where is the closing parenthesis on the printf statement?

 

[nenyan]

ok,,,i found the error

 

[nenyan]

The problem is here:

Where is the closing parenthesis on the printf statement?

Thanks a lot

 

[LudusRex]

There are a few potential issues with your code that could be causing the unexpected output. First, it is important to note that C does not initialize arrays to 0 by default, so it is possible that the values in the array are not actually 0. To ensure that the array is initialized to 0, you can use the memset function from the <string.h> library.

Another potential issue could be with the printf statement. It appears that you are missing a format specifier for the value of i, which could be causing unexpected output. A corrected printf statement could be: printf("a[%d]=%e\n", i, a);

Additionally, it is not clear what your intention is with the second for loop. It is essentially just printing the values of the array again, which may not be necessary. If you are trying to reset the values of the array to 0, you can simply use the memset function mentioned earlier.

Finally, it is always a good practice to include comments in your code to explain what each line is doing. This can help with identifying potential issues and make your code more understandable to others.