A massless, frictionless pulley is suspended from a rigid rod

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In the discussed scenario, a massless, frictionless pulley supports two masses, m (50 kg) and M (60 kg), connected by a cord. The force analysis reveals that the net force equation is Mg - mg = (m + M)a, leading to the conclusion that the acceleration of mass m is upward and that of mass M is downward. The acceleration for mass m is calculated as (M - m)g/(M + m), while mass M experiences the same magnitude of acceleration but in the opposite direction. The direction of acceleration is contingent on the defined coordinate system, with the participant defining positive as upward. Thus, mass m accelerates upward while mass M accelerates downward.
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A massless, frictionless pulley is suspended from a rigid rod. Two masses, m (50 kg) and M (60 kg), are suspended on either side of the pulley, respectively, by a light, inextendable cord. Determine the accelerations of the masses.

I drew the force diagrams of both; there is an upward tension force and a downward gravity force in each. Mg - mg = (m + M)a. Now acceleration of block m is (M - m)g/(M + m) upward and block M's acceleration is the same but downward. So does m have a positive acceleration while M has a negative acceleration?

Thanks.
 
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Could be either, it depends upon how you define your coordinate system. Is postive up or down?
 
I guess I define positive as going up on the coordinate sys. In the problem, m is pulled up while M goes down.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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