A non-empty intersection of closures of level sets implies discontinuity

  • #1
pasmith
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Let [itex]X[/itex] and [itex]Y[/itex] be topological spaces, and suppose [itex]f: X \to Y[/itex] is such that there exist distinct points [itex]c[/itex] and [itex]c'[/itex] of [itex]Y[/itex] such that [tex]
S = \overline{f^{-1}(\{c\})} \cap \overline{f^{-1}(\{c'\})} \neq \varnothing.[/tex] What conditions must be placed on [itex]X[/itex] and [itex]Y[/itex] so that it follows that [itex]f[/itex] is discontinuous at each point of [itex]S[/itex]? (Note that [itex]f^{-1}(\{c\}) \cap f^{-1}(\{c'\})[/itex] is necessarily empty: a function cannot take more than one value at any point of its domain.)

The statement appears to hold if [itex]X[/itex] and [itex]Y[/itex] are (locally) Euclidean, as for example [tex]
\mathbb{R}^2 \to \mathbb{R} : (x,y) \mapsto \begin{cases} \frac{x^2 - y^2}{x^2+ y^2} & (x,y) \neq (0,0) \\ \mbox{(any real number)} & (x,y) = (0,0) \end{cases}[/tex] in the limit [itex](x,y) \to (0,0)[/itex] or [tex]
[0, \infty) \to \mathbb{R} : x \mapsto \begin{cases} \sin (x^{-1}) & x \neq 0 \\
\mbox{(any real number)} & x = 0 \end{cases}[/tex] in the limit [itex]x \to 0[/itex], but does it hold between more general spaces?

We do have the following constraints:
  • If [itex]X[/itex] is discrete, then [itex]f[/itex] is necessarily continuous.
  • If [itex]Y[/itex] is indiscrete, then [itex]f[/itex] is necessarily continuous.

My idea is that for each [itex]x \in S[/itex] we can construct two distinct sequences, [itex]x_n \in f^{-1}(\{c\})[/itex] and [itex]x_n' \in f^{-1}(\{c'\})[/itex] having [itex]x[/itex] as their common limit, so that [tex]
\lim_{n \to \infty} f(x_n) = c \neq c' = \lim_{n \to \infty} f(x_n')[/tex] and [itex]f[/itex] is discontinuous at [itex]x[/itex]. But this assumes that limits in [itex]X[/itex] and [itex]Y[/itex] are unique.
 
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  • #2
pasmith said:
My idea is that for each [itex]x \in S[/itex] we can construct two distinct sequences, [itex]x_n \in f^{-1}(\{c\})[/itex] and [itex]x_n' \in f^{-1}(\{c'\})[/itex] having [itex]x[/itex] as their common limit, so that [tex]
\lim_{n \to \infty} f(x_n) = c \neq c' = \lim_{n \to \infty} f(x_n')[/tex] and [itex]f[/itex] is discontinuous at [itex]x[/itex]. But this assumes that limits in [itex]X[/itex] and [itex]Y[/itex] are unique.
That works. It points us towards requiring the Hausdorff condition for space ##Y##, which is perhaps the most commonly required condition in topology - so likely what the examiner was aiming for.
I wonder whether the weaker condition of preregularity would suffice. To investigate that we'd need to consider what happens in a preregular, non-Hausdorff space where the above points ##c## and ##c'## are not topologically distinguishable.
 

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