A Person Pushes a lawn Mower. Physics question Need

  • Thread starter alexparker
  • Start date
  • Tags
    Physics
In summary, the person is pushing a 20kg lawnmower at a constant speed with a force of 100N at a 35 degree angle to the horizontal. The horizontal retarding force is the force that opposes the motion of the lawnmower. The normal force by the ground on the mower is equal to the vertical component of the applied force. In order to give the lawnmower a velocity of 2.0m/s in 2.5 seconds, the person must exert a force to overcome the resistive force and assume that the initial speed is at rest.
  • #1
alexparker
18
0
A Person Pushes a lawnmower of mass 20kg at a constant Speed with a force of 100N directed along the handle, which is at 35 Degrees to the horizontal



A) What is the horizontal Retarding force on the mower? I have already done this but can you please explain what Horizontal Retarding Force Is

B) What is the Normal Force by the ground on the mower?

C) What force must the person exert on the lawnmower in order to give it a velocity of 2.0m/s in 2.5 seconds? It doesn't say the initial speed, so should i assume it is from rest?
 
Physics news on Phys.org
  • #2
There is some sort of resistive force the person pushing must overcome before the lawnmower can move. Though does the question mean at constant velocity or speed?
 
  • #3
B) What is the Normal Force by the ground on the mower?

The mower isn't going to be moving at all along the vertical axis so the normal force and the vertical component of the applied force are going to cancel.

C) What force must the person exert on the lawnmower in order to give it a velocity of 2.0m/s in 2.5 seconds? It doesn't say the initial speed, so should i assume it is from rest?

I think it's safe to make that assumption.
 

Related to A Person Pushes a lawn Mower. Physics question Need

1. How does the force applied by the person affect the motion of the lawn mower?

The force applied by the person to the lawn mower causes an acceleration in the direction of the force. This acceleration is dependent on the mass of the lawn mower and the magnitude of the force applied.

2. What factors determine the amount of work done by the person in pushing the lawn mower?

The amount of work done by the person in pushing the lawn mower is determined by the force applied, the distance over which the force is applied, and the angle between the force and the direction of motion. This can be calculated using the formula W = Fd cosθ, where W is work, F is force, d is distance, and θ is the angle between the force and the direction of motion.

3. What role does friction play in this scenario?

Friction plays a significant role in the motion of the lawn mower. It acts in the opposite direction to the motion of the lawn mower, making it harder for the person to push it. In order to overcome this frictional force, the person must apply a greater force to achieve the desired motion.

4. How does the slope of the ground affect the effort required to push the lawn mower?

The slope of the ground affects the effort required to push the lawn mower in two ways. Firstly, if the ground is sloped upwards, the person will have to exert more force to lift the lawn mower against gravity. Secondly, if the ground is sloped downwards, the person will have to apply a force to prevent the lawn mower from rolling away due to gravity.

5. How does the weight of the lawn mower impact the person's ability to push it?

The weight of the lawn mower plays a significant role in the person's ability to push it. A heavier lawn mower will require more force to accelerate and maintain its motion, making it more difficult for the person to push. Additionally, the weight of the lawn mower will also affect the amount of work done by the person, as more work is required to move a heavier object over the same distance.

Similar threads

  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
6
Views
5K
  • Introductory Physics Homework Help
Replies
18
Views
12K
  • Introductory Physics Homework Help
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
3K
  • Introductory Physics Homework Help
Replies
4
Views
4K
  • Introductory Physics Homework Help
Replies
6
Views
6K
  • Introductory Physics Homework Help
Replies
4
Views
21K
  • Introductory Physics Homework Help
Replies
2
Views
3K
Back
Top