A positronium atom decays into two photons c+c=c

In summary, a positronium "atom" decays into two photons c+c=c, traveling antiparallel to each other at the speed c away from the origin of decay. This means that the photons are also traveling away from each other at the speed c. This can be understood using rapidity, where the left-traveling photon is infinitely far away from the origin of decay and the right-traveling photon is infinitely far away from the left-traveling photon. The relativistic speed composition formula shows that the speed of light always remains c, even when adding or subtracting it to another speed. However, it is important to note that there is no inertial reference frame in which a photon is at rest, so it
  • #1
Loren Booda
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A positronium "atom" decays into two photons c+c=c

A positronium "atom" decays into two photons traveling antiparallel to each other, both at the speed c away from the origin of decay. How can one appreciate the fact that they are also traveling away from one another at the speed c?
 
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  • #2
Here is a [possibly unfamiliar] way to appreciate this... using rapidity, the additive parameter akin to an angle. In 1+1 Minkowski spacetime, as measure of separation between [future-pointing causal] "rays" from the origin, a light ray is infinitely far away from every other ray... in the sense, one would have to boost by an infinite amount to get to or from that light ray. [It is along these lines that one can explain why one can never get a massive object to travel at the speed of light.]

So, the left-traveling photon is infinitely far away (in rapidity) from the origin of decay... as well as infinitely far away (in rapidity) from the right-traveling photon.

For a formula, one can write down the usual "relative velocity formula" in terms of the identity for the hyperbolic tangent of a difference of two rapidities [angles]. I'm too lazy to do this now.
 
  • #3
Loren Booda said:
A positronium "atom" decays into two photons traveling antiparallel to each other, both at the speed c away from the origin of decay. How can one appreciate the fact that they are also traveling away from one another at the speed c?

Suggestion:

In the relativistic speed composition formula:

w=(u+v)/(1+uv/c^2) make u=v=c

It appears that this comes up all the time because "it offends our senses".
What can you do, the laws of physics may be counterintuitive sometimes. :!)
 
  • #4
Can any of you construct a schematic which demonstrates this addition of light speeds relative to the origin, resulting in light speed correlative to the photons themselves? That is, show the situation in picture form.
 
  • #5
Loren Booda said:
Can any of you construct a schematic which demonstrates this addition of light speeds relative to the origin, resulting in light speed correlative to the photons themselves? That is, show the situation in picture form.

The formula is a nonlinear function, (a type of hyperbolic surface) so, try using Mathematica :

w(u,v)=(u+v)/...
 
  • #6
Loren Booda said:
resulting in light speed correlative to the photons themselves?

In relativity, there is no inertial reference frame in which a photon is at rest. Therefore one cannot talk about the speed of a photon relative to another photon, in the same sense that one can talk about the speed of a photon relative to you or any other massive object (which speed is always c, of course).
 
  • #7
jtbell said:
In relativity, there is no inertial reference frame in which a photon is at rest. Therefore one cannot talk about the speed of a photon relative to another photon, in the same sense that one can talk about the speed of a photon relative to you or any other massive object (which speed is always c, of course).

True. Despite this the formulas STILL hold.
I can see what the author of this thread wanted: does the formula still hold for u=c and v=-c? The answer is "yes". (it will disappoint a lot of antirelativists). Here is why:



w(u,-c)=(u-c)/(1-uc/c^2)=c! for ANY u (including u=c)
 

FAQ: A positronium atom decays into two photons c+c=c

What is a positronium atom?

A positronium atom is a bound state of an electron and its antiparticle, the positron. It is the lightest known atom and has a similar structure to a hydrogen atom, with the electron and positron orbiting around a common center of mass.

How does a positronium atom decay?

A positronium atom decays through the annihilation of the electron and positron, resulting in the release of two photons with equal energy in opposite directions.

What is the significance of a positronium atom decaying into two photons?

The decay of a positronium atom into two photons is significant because it follows the laws of conservation of energy and momentum, providing evidence for the existence of antimatter and the validity of quantum mechanics.

What is the energy and wavelength of the photons released during the decay of a positronium atom?

The energy of the photons released during the decay of a positronium atom is equal to the rest mass of the positron and electron combined, which is approximately 1 MeV. The wavelength of the photons is in the gamma ray range, around 0.001 nanometers.

How is a positronium atom used in scientific research?

Positronium atoms are used in various fields of scientific research, including positron emission tomography (PET) imaging, particle physics experiments, and studies of matter-antimatter interactions. They also serve as a simplified model for studying the behavior of atoms in extreme conditions.

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