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I have explained it lots of times. I don't know what else I can say. Devlin never mentions that if it's possible to calculate the expected gain as a function of the amount in the first envelope, the result of the calculation is the solution of a different problem.matt grime said:I completely fail to see what it is that you state is missing from the explanation in, say, Devlin, that is actually missing. All of the things you claim are required for a full explanation of the paradox are in that linked article.
I guess you can say that, but this "only situation there is" is not the situation that was specified in the problem we're working with! Read post #1 again. We don't know the prior distribution!matt grime said:If you get the probabilities correct, then it tells you the correct answer in *every* situation, well, the *only* situation that there is.
Yes, the correct answer to the wrong problem.matt grime said:It really isn't hard: if you use the correct probabilities then you get the correct answer.
No it isn't. The first step of the explanation is to realize that the probabilities in the calculation of E(B|A=a)-E(A|A=a) depend on the prior distribution. The second and final step is to realize that that means that E(B|A=a)-E(A|A=a) will tell us what the correct decision is in a situation where both a and the prior distribution is known, but not in the situation that was specified in the problem!matt grime said:The explanation of the paradox is that the probabilities that are shoved in are nonsense.
Devlin doesn't do the second step. Everything he does after the first step is irrelevant.
Unless Hurkyl has told you privately that he meant something other than what he said, you are wrong. He quoted two sencences of mine and said that he can't follow "either of these assertions". Each sentence is one assertion. The 'first one' is that Devlin claims that the cause of the paradox is the confusion of prior and posterior probabilities.matt grime said:No, it isn't. The 'first one' was that you asserted that the expected gain from swapping is zero.
And stop saying that I have asserted that E(B|A=a)-E(A|A=a) is zero! I have never said that.
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