- #1
Blitzp22
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Homework Statement
A proton is fired from far away towards the nucleus of a mercury atom. Mercury is element number 80, and the diameter of the nucleus is 14.0 fm. If the proton is fired at a speed of 32100000 m/s, what is its closest approach to the surface of the nucleus (in fm)? Assume that the nucleus remains at rest.
Homework Equations
U=kq1q2/r
kinematic equation
K = 1/2 m v^2
The Attempt at a Solution
So I got this far
1/2(1.67E-27)(3.21E7)^2=(9E9)(q1)(q2)/7fm
but I don't know what to do about the q1 and q2 to get my final answer. Hmmmm toughy