- #1
Ahmed1029
- 109
- 40
in this example in Griffiths' electrodynamics, he says the following :(Figure 3.7 shows
a simple electrostatic configuration, consisting of four conductors with charges
±Q, situated so that the plusses are near the minuses. It all looks very comfort-
able. Now, what happens if we join them in pairs, by tiny wires, as indicated in
Fig. 3.8? Since the positive charges are very near negative charges (which is where
they like to be) you might well guess that nothing will happen—the configuration
looks stable.
Well, that sounds reasonable, but it’s wrong. The configuration in Fig. 3.8 is
impossible. For there are now effectively two conductors, and the total charge
on each is zero. One possible way to distribute zero charge over these conductors is to have no accumulation of charge anywhere, and hence zero field everywhere)
I feel like there are gaps in this explanation, that is, don't know if he implicitly invoked the first uniqueness theorem here