A question and no idea what to do

[ouse]

determine the inital velocity of a projectile that is luncked horizantaly and falls 1.5m while moving 16m horizantaly
i tried everything all i figerd out is that they r displacmednts the accelaration is 9.8 and nothing i don't have enogh info to do anything
please help me

 

[Päällikkö]

Divide the motion into x and y components and deal with them as if you were dealing with one-dimensional motion.

 

[ouse]

can u please elaborate

 

[ouse]

and any way that doesn't work becuse i have no angles to detrime wat the x and y components are

 

[ouse]

that would only work if these were vectors not displacment

 

[Päällikkö]

Well...
$$x = v_0t$$
$$0 = y_0 -\frac{1}{2}gt^2$$
Does that help at all?

 

[ouse]

yeah it helped i acctualy figerd the question thanks sooo much

 

[ouse]

now can u please look at my other thread and please ohh please help with question 1 b,c and q 2

 

[Päällikkö]

yeah it helped i acctualy figerd the question thanks sooo much

Glad to hear that :).

Did you understand where the equations I gave came from?

 

[ouse]

ummm well yeah for one of them

 

[ouse]

u assumed viy is 0 and took it our of the equation right

 

[Päällikkö]

The full equations:
$$x = x_0 + v_{x0}t + \frac{1}{2}a_xt^2$$
$$y = y_0 + v_{y0}t + \frac{1}{2}a_yt^2$$
Let $x_0 = 0$. As the projectile's fired horizontally: $v_{y0} = 0$ thus $v_{x0} = v_0$. No force affects the projectile in x-direction, so: $a_x = 0$. In y-direction: $a_y = -g$ (- as it's downward). The final altitude of the projectile is $y = 0$.

Hence
$$x = v_0t$$
$$0 = y_0 -\frac{1}{2}gt^2$$

 

[ouse]

i was woundring if u could help me with the other thread please help me i really need it i have a test i need to pass

 

[ouse]

thx for the explination