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Newton's law of universal gravitation states that every mass in the universe attracts every other mass with a force proportional to the product of their masses.
See website for diagrams: http://hyperphysics.phy-astr.gsu.edu/hbase/forces/isq.html
Inverse Square Law, Gravity
As one of the fields which obey the general inverse square law, the gravity field can be put in the form shown below, showing that the acceleration of gravity, g, is an expression of the intensity of the gravity field.
Other applications of the inverse square law Electric field Light Sound Radiation
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Gravity concepts
HyperPhysics***** Mechanics R Nave
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Unquote:
Place the aircraft above the surface of the Earth to the elavation of 10000ft. The distance from the Earth will calculate how much of the Earth's sphere it is exposed to and therefore the measure of gravitational pull it is feeling from the Earth. This measurement will not be inversed as the craft is now the point of focus. It will be the opposite of inversed. Now measure the aircraft's mass weight. It's weight inversed by the measurement of distance will calculate the amount of gravitational pull it is effecting on the Earth. Take the measurement of gravitational pull felt by the craft from the Earth and the measurement of gravitational pull felt by the Earth from the craft. Add these together. This is the increase in gravitational pull that an aircraft of this weight will experience at this elevation above this planet. (This obviously does not take into acount lift, induced drag, thrust, pressure, temperature or density. Only weight, elevation and gravity drag. )
If this is not the case, can anyone explain why please?
See website for diagrams: http://hyperphysics.phy-astr.gsu.edu/hbase/forces/isq.html
Inverse Square Law, Gravity
As one of the fields which obey the general inverse square law, the gravity field can be put in the form shown below, showing that the acceleration of gravity, g, is an expression of the intensity of the gravity field.
Other applications of the inverse square law Electric field Light Sound Radiation
Index
Gravity concepts
HyperPhysics***** Mechanics R Nave
Go Back
Unquote:
Place the aircraft above the surface of the Earth to the elavation of 10000ft. The distance from the Earth will calculate how much of the Earth's sphere it is exposed to and therefore the measure of gravitational pull it is feeling from the Earth. This measurement will not be inversed as the craft is now the point of focus. It will be the opposite of inversed. Now measure the aircraft's mass weight. It's weight inversed by the measurement of distance will calculate the amount of gravitational pull it is effecting on the Earth. Take the measurement of gravitational pull felt by the craft from the Earth and the measurement of gravitational pull felt by the Earth from the craft. Add these together. This is the increase in gravitational pull that an aircraft of this weight will experience at this elevation above this planet. (This obviously does not take into acount lift, induced drag, thrust, pressure, temperature or density. Only weight, elevation and gravity drag. )
If this is not the case, can anyone explain why please?