- #1
tamiry
- 10
- 0
Homework Statement
Hi
we have Lorentz operators
[itex]J^{\mu\nu} = i(x^{\mu}\partial^{\nu} - x^{\nu}\partial^{\mu})[/itex]
and these have
[itex][J^{\mu\nu}, J^{\rho\sigma}] = i(\eta^{\nu\rho}J^{\mu\sigma} + \eta^{\mu\sigma}J^{\nu\rho} - \eta^{\mu\rho}J^{\nu\sigma} - \eta^{\nu\sigma}J^{\mu\rho})[/itex]
Now define generalized rotation operators, for i, j, k space coordinates
[itex]M^{i} = \epsilon_{ijk}J^{jk}[/itex]
Show that [itex]M^{i}[/itex] have the SU(2) algebra. i.e.
[itex][M^{i}, M^{j}] = i\epsilon_{ijk}M^{k}[/itex]
Homework Equations
(all is above)
The Attempt at a Solution
I've done a few attempts and failed. so I tried taking an example
[itex]M^{1}= \epsilon_{123}J^{23}+\epsilon_{132}J^{32} = J^{23} - J^{32}[/itex]
[itex]M^{2}= \dots = J^{31} - J^{13}[/itex]
and now
[itex][M^{1},M^{2}] = [J^{23}, J^{31}] - [J^{32}, J^{31}] + [J^{23}, J^{13}] - [J^{32}, J^{13}][/itex]
well [itex]J^{ij} = -J^{ji}[/itex] so the second term negates the first one ([itex]J^{32} for J^{23}[/itex]) and like wise the fourth and third term. So all in all I get zero. and that's no SU(2) :(
where did I go wrong?
thanks a lot for reading this
Tamir