- #1
MNWO
- 10
- 0
Hi, so i have finished this question but I am not sure if I did it right. Could you guys check it and tell me if its right or show me where i went wrong.
This is the question:
A space vehicle traveling At a velocity of 1400m/s separates by a controlled explosion into two sections of mass 859kg (m1) and 250 kg (m2). The two parts then carry on in the same direction with the heavier rear section moving 120m/s slower than the lighter front section. Determine the final velocity of each section.
Mass1=859 kg
Mass2:250kg
M1+M2=1109 kg
1109kg x 1400m/s = 1552600 N
So the vehicle is creating 1552600N of force, the faster part shouldbe moving slower by 120m so
1552600-120=1552480
1552480/1109 (m1+m2)
=1399.89 m/s
speed of M1 is 1399.89m/s
So the speed of M2 will be 1399.89+120
M2=1519.89m/s
This is the question:
A space vehicle traveling At a velocity of 1400m/s separates by a controlled explosion into two sections of mass 859kg (m1) and 250 kg (m2). The two parts then carry on in the same direction with the heavier rear section moving 120m/s slower than the lighter front section. Determine the final velocity of each section.
Homework Equations
Mass1=859 kg
Mass2:250kg
M1+M2=1109 kg
1109kg x 1400m/s = 1552600 N
The Attempt at a Solution
So the vehicle is creating 1552600N of force, the faster part shouldbe moving slower by 120m so
1552600-120=1552480
1552480/1109 (m1+m2)
=1399.89 m/s
speed of M1 is 1399.89m/s
So the speed of M2 will be 1399.89+120
M2=1519.89m/s