A square root problem

  • #1
littlemathquark
19
5
Homework Statement
##\sqrt{\dfrac{3^8+5^8+34^4}2} =?##
Relevant Equations
None
I can't find a short solution without using calculator.
 
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  • #2
Consider the prime factors of all the components
Oh, that only works if the 3 upper terms are multiplied.
Adding them makes only for a big unwieldy number. Don't see how to simplify it at all.
 
  • #3
Do 3, 5, and 34 (or their prime factors) have any properties in common that might help? Especially helpful if there are terms that might cancel when expanded.
 
  • #4
Ibix said:
Do 3, 5, and 34 (or their prime factors) have any properties in common that might help? Especially helpful if there are terms that might cancel when expanded.
##3^8+5^8+34^4=9^4+25^4+34^4=9^4+25^4+(9+25)^4##
That's all and I'm stuck.
 
  • #5
Interesting! Not what I had in mind at all, but it also works.

What do you get if you expand that? I found it helpful to write ##x=3## and ##y=5## so I didn't lose track of my special numbers among all the other ones.

If the expansion is going to help you in this particular problem, what has to be true about it?
 

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