A Trick to Memorizing Trig Special Angle Values Table

  • Thread starter Thread starter benorin
  • Start date Start date
  • Tags Tags
    Angle Table Trig
AI Thread Summary
Memorizing trigonometric special angle values is crucial for calculus, as evaluations often involve these angles. A suggested method is to create a table with angles in both degrees and radians, filling in sine, cosine, and tangent values systematically. The sine function starts at zero and follows a pattern based on the square roots of integers divided by four. Understanding the unit circle and basic triangle geometry aids in deriving these values. This approach simplifies learning and retention of essential trigonometric functions.
benorin
Science Advisor
Insights Author
Messages
1,442
Reaction score
191
In calculus classes when you are asked to evaluate a trig function at a specific angle, it’s 99.9% of the time at one of the so-called special angles we use in our chart. Since you are likely to have learned degrees first I’ll include degree angles in the first chart, but after that, it’s going to be radian only.
Begin by setting up the table on scratch paper as follows:
$$\begin{array}{ l| |c|c|c|c|c } \theta & 0 = 0º & \tfrac{\pi}{6} = 30º & \tfrac{\pi}{4}=45º & \tfrac{\pi}{3}=60º & \tfrac{\pi}{2}=90º \\ \hline\hline \sin\theta &   &   &  &   &    \\ \hline \cos\theta &   &    &    &    &    \\ \hline \tan\theta &    &    &    &   &    \\ \hline \end{array} $$
Then remember ##\sin\theta## starts at zero, fill in the pattern
$$\begin{array}{ l| |c|c|c|c|c } \theta & 0 & \tfrac{\pi}{6} & \tfrac{\pi}{4} & \tfrac{\pi}{3} & \tfrac{\pi}{2} \\ \hline\hline\sin\theta & \tfrac{\sqrt{0}}{2} & \tfrac{\sqrt{1}}{2} & \tfrac{\sqrt{2}}{2} & \tfrac{\sqrt{3}}{2} & \tfrac{\sqrt{4}}{2} \\...

Continue reading...
 
Last edited by a moderator:
  • Like
Likes yucheng, sysprog, Wrichik Basu and 4 others
I think I'll make this compulsory reading for my Maths students!
 
  • Like
  • Informative
Likes symbolipoint, benorin and Greg Bernhardt
In our junior classes, we learned it in a similar way:
##\theta~\rightarrow##​
0° = 0​
30° = ##\dfrac{\pi}{6}##​
45° = ##\dfrac{\pi}{4}##​
60° = ##\dfrac{\pi}{3}##​
90° = ##\dfrac{\pi}{2}##​
##\sin \theta##​
##\sqrt{\dfrac{0}{4}}##​
##\sqrt{\dfrac{1}{4}}##​
##\sqrt{\dfrac{2}{4}}##​
##\sqrt{\dfrac{3}{4}}##​
##\sqrt{\dfrac{4}{4}}##​
##\cos \theta##​
##\sqrt{\dfrac{4}{4}}##​
##\sqrt{\dfrac{3}{4}}##​
##\sqrt{\dfrac{2}{4}}##​
##\sqrt{\dfrac{1}{4}}##​
##\sqrt{\dfrac{0}{4}}##​
##\tan \theta##​
##\sqrt{\dfrac{0}{4 - 0}}##​
##\sqrt{\dfrac{1}{4 - 1}}##​
##\sqrt{\dfrac{2}{4 - 2}}##​
##\sqrt{\dfrac{3}{4 - 3}}##​
##\sqrt{\dfrac{4}{4 - 4}}##​
 
Last edited:
  • Like
Likes bublik_c_makom and benorin
"Trick"? The very basics of triangle Geometry and the Pythagorean Theorem, and The UNIT CIRCLE.

Easily enough done, drawing a Unit Circle and judging Sines and Cosines, and whichever other of the functions to derive what you need. Degree measures 30, 45, 60, 0, and 90, and 180 are the easy ones and are commonly used "Reference" angles.
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Back
Top