- #1
MHD93
- 93
- 0
What I know from the chain rule is that if y and u are differentiable with respect to x then dy/dx = (dy/du)*(du/dx)
Now, why is this example doesn't work:
y = x^2
u = c
then we have dy/dx = (dy/du) * (du/dx) = (dy/du) * 0 = 0 doesn't equal 2x
I want an answer irrelated to the chain rule, not explanations involving limits only.
THANKS
Now, why is this example doesn't work:
y = x^2
u = c
then we have dy/dx = (dy/du) * (du/dx) = (dy/du) * 0 = 0 doesn't equal 2x
I want an answer irrelated to the chain rule, not explanations involving limits only.
THANKS