Absolute Extrema of 2x - (x-2) on [0,1], [-3,4]

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To find the absolute extrema of the function f(x) = {2x} - {x-2} on the intervals [0,1] and [-3,4], it is essential to analyze the function as a piecewise function. The derivative f'(x) = 2 - {1} does not provide clear information, necessitating evaluation of f(x) at critical points and endpoints within each interval. For the interval [0,1], determine the values of {2x} and {x-2} to assess extrema. In the interval [-3,4], break down the function further into segments to analyze behavior at key points, particularly around 0 and 2 where the derivative may not be defined. Understanding the piecewise nature of the function is crucial for accurately identifying the absolute extrema.
portillj
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{} these brackets are going to represent the absolute value lines
the problem states
find the absolute extrema of the given function on each individual interval:
f(x)= {2x} - {x-2}
a) [0,1]
b) [-3, 4]

I know I need the derivative of the equation but it does not really give a good derivative since it would be f'(x)= 2 - {1}
 
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well, first what is {2x} equal to when x is from [0,1], als owhat is the value of {x-2}, do the same thing in the other interval!
 
You could also break the function up into the intervals (-\infty,0), [0,2), and [2,\infty) and write f as a piecewise function. Then, you can find the derivative on each of those open intervals (remember that the derivative won't necessarily be defined at 0 and 2).
 
how am i suppose to do tat
 
portillj said:
how am i suppose to do tat

Do u know how a piecewise defined function looks like? Well, to do that in this case you need to follow both my hints and also PingPong's hints!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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