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fuzzy
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Homework Statement
The protein oxyhemoglobin has the following molar absorbance coefficients:
[tex]\epsilon[/tex]276 nm = 3.44 x10[tex]^{4}[/tex]M[tex]^{-1}[/tex]cm[tex]^{-1}[/tex]
[tex]\epsilon[/tex]415 nm = 1.25 x 10[tex]^{5}[/tex]M[tex]^{-1}[/tex]cm[tex]^{-1}[/tex]
If a solutioin of oxyhemoglobin has an absorbance at 415nm of 0.234,
a) What is the concentration at 415nm?
b) What is the absorbance at 276 nm?
Homework Equations
A=[tex]\epsilon[/tex]bc, where A is absorbance, [tex]\epsilon[/tex] is the molar absorbance coefficient in M[tex]^{-1}[/tex]cm[tex]^{-1}[/tex], b is the length of light path through the cell in cm, and c is concentration in mol/L.
(I don't know if this one is needed...)
[tex]\frac{As}{Au}[/tex]=[tex]\frac{Cs}{Cu}[/tex]
where As and Au are absorbance of the standard and unknown and Cs and Cu are concentration of the standard and unknown.
The Attempt at a Solution
Can someone give me a hint at where to start here? I can't see how to do the problem without at least 1 of the concentration values or a light path length. Do I assume that the concentrations remain the same at 276 and 415?