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Hypro96
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EXPERIMENT ABSORPTION OF γ - RADIATION IN LEAD AND CALCULATION OF ABSORPTION COEFFICIENT µ
Using equation (3) / slope of graph lnC vs d - estimate µ. This should be in units of per meter (m-1 ).
The formula in the analysis are as follows :
You may ignore the decimal point at the RANGE=10 setting on the scaler/timer ! so the count then turns out to be whole numbers .
Data (where d is the thickness of the lead sheets):
y = -0.0116x +0.0886 in excell with the tread line . I hope the axis were right :P .
So μ≈ -0.0116
Using the equation was hard for me as I'm not sure which component is which , i feel like what I am doing is awfully wrong. I tried to work out μ by subbing in values from the table to C(d) and C0 equation 2 i did the same for the 3 equation and tried to solve with rules of logs , taking C0 as background count of 28 .
I would appreciate any explanation so i can do the calculation and see what happens .
Using equation (3) / slope of graph lnC vs d - estimate µ. This should be in units of per meter (m-1 ).
The formula in the analysis are as follows :
1. I = I0 e-μd
2. C(d) = C0 e-μd
2. C(d) = C0 e-μd
3. lnC = lnC0 -μd
Data (where d is the thickness of the lead sheets):
- d(m) = 0.0121 ,0.0063 ,0.0025 ,0.0184 ,0.0146 ,0.008
- Count/min = 636 ,1050 ,1474 ,424 ,454 ,700
- C (counts/min) - background count = 28
- Find ln C
y = -0.0116x +0.0886 in excell with the tread line . I hope the axis were right :P .
So μ≈ -0.0116
Using the equation was hard for me as I'm not sure which component is which , i feel like what I am doing is awfully wrong. I tried to work out μ by subbing in values from the table to C(d) and C0 equation 2 i did the same for the 3 equation and tried to solve with rules of logs , taking C0 as background count of 28 .
I would appreciate any explanation so i can do the calculation and see what happens .
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