- #1
shrutij
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Homework Statement
A 97.4 kg basketball player can leap straight up in the air to a height of 71.9 cm. The player bends his legs until the upper part of his body is dropped by 61.2 cm, then he begins his jump. With what speed must the player leave the ground to reach a height of 71.9 cm?
What was his acceleration, assumed to be constant, as he jumped (before his feet left the ground)?
Homework Equations
F= ma
player's weight = m x 9.8 m/s2= 955 N
The Attempt at a Solution
I got the first question (with what speed much the player leave the ground) right, vf=3.75 m/s.
I know that the acceleration must increase to overcome the force of your weight as he jumps, but I'm unsure how to calculate what that constant acceleration would be, and how to calculate that from the values given.
HELP PLEASE!