- #1
PhysicsStudnt
- 19
- 1
In terms of calculus, How do i prove that the area under the acceleration time graph gives me the change in KE / mass...
Attempt at solution...
Area under the graph of a function y = f(x) is given by ∫y dx
Therefore area under acceleration displacement graph is ∫a ds (considering the function to be a=f(s))
=> ∫f/m ds
=> 1/m (∫f.ds)
=> 1/m (W) ...[work done = ∫f.ds ]
=> ΔKE/m ...[W = ΔKE]
1. Is this proof correct mathematically and theoretically...
2. Is there a different or better proof...
Attempt at solution...
Area under the graph of a function y = f(x) is given by ∫y dx
Therefore area under acceleration displacement graph is ∫a ds (considering the function to be a=f(s))
=> ∫f/m ds
=> 1/m (∫f.ds)
=> 1/m (W) ...[work done = ∫f.ds ]
=> ΔKE/m ...[W = ΔKE]
1. Is this proof correct mathematically and theoretically...
2. Is there a different or better proof...