Acceleration due to gravity lab

In summary, the students used a pendulum to measure the period. They then used the period and the length of the pendulum to calculate the value of "g".
  • #1
hotshot1kille
22
0

Homework Statement



We did a lab using a pendulum attached to a string about 1.12m long. We let it go from 20 degrees and counted 10 cycles and recorded how much time it took for the pendulum to complete 10 cycles. This lab is done assuming, there is no air resistance or any other force other than just gravity. We did 3 test cases.

Test case 1- time it took for the pendulum to complete 10 full cycles is 23.41 s.

Test case 2- time it took for the pendulum to complete 10 full cycles is 23.41 s.

Test case 3- time it took for the pendulum to complete 10 full cycles is 23.44 s.

Find the average time for 10 cycles.

Using this average time, calculate the period of the pendulum.

Using the period of the pendulum and its length, calculate the value of "g".


I don't know how to do average time, and if i get the average time wrong then i get number 2 wrong and then my answer for number 3 will be wrong. So i did make an attempt, can someone check if i am doing it right and if my answer seem fine for all questions. Please and Thank you.



Homework Equations



T= 2∏ √ L/g

Period: Δt/Nc

Average time for 10 cycles : Δt/ Nc


The Attempt at a Solution



1. Find the average time: Test case 1: 23.41s/10 =2.341 seconds per cycle.

Test case 2- 23.41s/10 =2.341 seconds per cycle.

Test case 3- 23.44/10 = 2.344 seconds per cycle.

2. Period= Δt/ Nc

Test case 1 and 2: 2.341s / 10 = 0.2341

Test case 3: 2.344/10= 0.2344


3. Find g.

4∏^2 (L)
---------- = g
T^2

4∏^2 (1.12m)
--------------- = g
0.2341^2

g= 806.81 m/s^2
 
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  • #2
The average of 2.341, 2.341 and 2.344 is their sum divided by three. That is, about ten times the .2341 you used in the calc. That will give you a decent value for g, but not a great one. In my experience, it takes considerable practise to get good times and far better to count 100 swings rather than 10. Also, mistakes can be made in measuring the length - not just the length of the string, but the distance from the pivot point to the center of mass of the bob.
 
  • #3
So average time is : (23.41+23.41+23.44) / 3 = 23.42

period= (23.42)/10 = 2.342

so then gravity would equal to

4∏^2 (1.12m)
--------------- = g
2.342^2

g= 8.06 m/s^2

does this seem fine?
 
  • #4
Yes, the calc looks good! How about the measurement of L; did you include the distance from the end of the string to the center of the bob? If not, take an estimate and add it.
 
  • #5
Yea what we did in class was that they were already made. We just got up and took one, the lab says it has to be roughly within 1.2- 1.5m. I told my teacher i have about 1.1m, and he said it is fine, because like the 0.1m won't make a big difference for such a small calculation. He also mentioned that imagining that there is only gravity acting upon it do not worry about resistance, shape of the ball and how round it is.
 
  • #6
Well, if you added .1 to the length, you would have 8.9 instead of 8.0 for your answer.
But I doubt if your bob was 20 cm long.

Students often get 9.6 to 10 m/s² from this experiment because air resistance, etc. really doesn't make much difference. Note that the time measurement is squared, so its error strongly affects the result. That's why it is important to go to great lengths to measure the time accurately.

It would be interesting to try to estimate the accuracy of your time measurements and perhaps deduce from that the accuracy of the calculated value for g. The stopwatch is very accurate, so your main error is going to be due to hitting the button at the wrong time. If you time something known to be very accurate, like a clock second had, you will probably find an error of something like 0.1 second. Try increasing or decreasing your average time by that much and see how it affects the result. Of course your average over 30 swings should reduce your error by a factor of sqrt(30) . . . unless there was some kind of consistent error in the timing process such as being faster at pressing start than in pressing stop due to anticipating the end of the tenth swing.
 
  • #7
Oh ok i see your point of view. Thank you so much i will fix it and get back to you.
 

FAQ: Acceleration due to gravity lab

What is the purpose of the "Acceleration due to gravity lab"?

The purpose of the lab is to measure the acceleration due to gravity on Earth and compare it to the theoretical value.

How is the acceleration due to gravity measured in the lab?

The lab typically involves using a pendulum or a free-falling object to measure the time it takes for the object to fall a certain distance. The acceleration due to gravity can then be calculated using the equation a = 2d/t^2, where d is the distance and t is the time.

What factors can affect the accuracy of the results in the "Acceleration due to gravity lab"?

Factors such as air resistance, friction, and human error can affect the accuracy of the results. It is important to minimize these factors as much as possible to obtain more accurate data.

What is the theoretical value of the acceleration due to gravity?

The theoretical value of the acceleration due to gravity on Earth is 9.8 m/s^2. However, this value may vary slightly depending on the location and altitude.

How is the acceleration due to gravity related to mass and distance?

The acceleration due to gravity is inversely proportional to the square of the distance between two objects and directly proportional to the mass of the objects. This means that the closer two objects are and the more massive they are, the stronger the gravitational force between them and the greater the acceleration due to gravity.

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