Acceleration of a Particle in an Elliptical Path

In summary, the problem is to determine the acceleration of a particle in an arbitrary position along the elliptical path of a flexible bar in a horizontal plane. The equations involved are the polar coordinates of the path and the equation for acceleration in cylindrical coordinates, and the assumption that z is constant due to the horizontal motion. The solution involves differentiation and the chain rule, and the use of symbols for proper notation.
  • #1
LisaSpace
1
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Homework Statement


Path of a particle attached to the end of a flexible bar is essentially an ellispe in the horizontal plane.

Determine the acceleration of the particle in an arbitrary position.

Homework Equations



The polar coordinates are:

R = ab/(b^2+(a^2-b^2)cos(theta)^2)^.5

theta(dot) = k/R^2

The Attempt at a Solution



I attempted to solve using the equation for acceleration in cylindrical coordinates, I'd write it out, but I'm not familiar with the code for math symbols.

I assumed z to be constant since motion was in a horizontal plane.

Is this the correct way to go about solving it? If it is then I'll will go and see where I messed up.

Thanks
 
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  • #2
LisaSpace said:

Homework Statement


Path of a particle attached to the end of a flexible bar is essentially an ellispe in the horizontal plane.

Determine the acceleration of the particle in an arbitrary position.

Homework Equations



The polar coordinates are:

R = ab/(b^2+(a^2-b^2)cos(theta)^2)^.5

theta(dot) = k/R^2

The Attempt at a Solution



I attempted to solve using the equation for acceleration in cylindrical coordinates, I'd write it out, but I'm not familiar with the code for math symbols.

I assumed z to be constant since motion was in a horizontal plane.

Is this the correct way to go about solving it? If it is then I'll will go and see where I messed up.

Thanks

If you know the particle position, then you should be able to get the acceleration through differentiation and the chain rule. So yes, carry on and show us where you think you are messing up. You can use the buttons labeled X2 and X2 for super and sub scripts. There are also various symbols for copy and paste in my signature.
 

FAQ: Acceleration of a Particle in an Elliptical Path

What is the formula for calculating acceleration in an elliptical path?

The formula for calculating acceleration in an elliptical path is a = v^2/r, where a is acceleration, v is the velocity of the particle, and r is the radius of the elliptical path.

How does acceleration change in an elliptical path?

In an elliptical path, the acceleration changes continuously as the particle moves along the path. This is because the velocity and radius are constantly changing, resulting in a changing value for acceleration.

What factors affect the acceleration of a particle in an elliptical path?

The acceleration of a particle in an elliptical path is affected by the velocity of the particle, the radius of the path, and the mass of the particle. Other factors such as air resistance or external forces can also play a role in the acceleration of the particle.

How is acceleration related to the shape of an elliptical path?

The shape of an elliptical path does not directly affect the magnitude of acceleration. However, the changing velocity and radius along the path can result in varying acceleration values.

Can acceleration in an elliptical path be negative?

Yes, acceleration in an elliptical path can be negative. This occurs when the particle is slowing down along the path, resulting in a negative value for acceleration. However, the magnitude of acceleration is always positive, as it is calculated using the velocity squared and the radius.

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