- #1
Shinaolord
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Accelerometer -- device on a parabolic track
EDIT: Picture of problem in its entirety farther down.
A device on a parabolic trac moves on the track described as y=x^2. Both in meters
A$ find an expression for acceleration using position.
B) what is a if x=20cm?
My solution.
First, I took dy/dx(x^2)=2x for velocity. We know the tangent line of a point on velocity is the acceleration. The tangent line is defined as the reciprocal of the function, the slope of the velocity is x/2. At .2m this equals .1 m/s^2 of acceleration.
Am I right?
EDIT: Picture of problem in its entirety farther down.
A device on a parabolic trac moves on the track described as y=x^2. Both in meters
A$ find an expression for acceleration using position.
B) what is a if x=20cm?
My solution.
First, I took dy/dx(x^2)=2x for velocity. We know the tangent line of a point on velocity is the acceleration. The tangent line is defined as the reciprocal of the function, the slope of the velocity is x/2. At .2m this equals .1 m/s^2 of acceleration.
Am I right?
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