Accumulation of Mass in Stellar Formation?

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In summary, the conversation discusses the potential role of dipolar attraction in stellar formation, specifically in dust clouds that accumulate mass through gravity. It is mentioned that higher order terms, such as the Earth's zonal quadrupole moment, can also play a significant role in satellite orbits. A comparison is made between the Earth's gravitational field and a dust cloud, with the conclusion that an extremely detailed model of either will have time-varying spherical harmonics coefficients. The conversation also touches on the concept of electric dipoles and van der Waal forces at the molecular level, and how they may play a role in stellar formation. However, it is noted that astronomers do not typically consider these forces in their models due to the numerical representations used
  • #1
maverick_starstrider
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The recent post by shamrock5585 got me thinking. Most models of stellar formation and stuff basically involve an accumulation of mass through gravity building larger and larger mass. However, even if we assume that all the particles are of neutral charge we can still expect a dipole-dipole force as the particles get closer (through taylor series expansion). However, (if we briefly consider gravity as a Newtonian force instead of in terms of general relativity) I would be inclined to think that, due to the very small size of the constant G, that the dipolar term (although it is of the order 1/r^3) would be dominant as the particles begin to closely pack and yet I don't think I've ever heard of dipolar attraction being an important factor of stellar formation (although I'm a computational quantum many-body guy not an astro guy).

I guess my question is, is dipolar attraction ever considered in these sorts of models?
 
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  • #2
The Earth (and any real astronomical object) is not a perfect sphere. A precision gravity model requires a treatment of the non-spherical shape. Spherical harmonics are one obvious choice. The obvious origin for such a spherical harmonics expansion is the center of mass. The center of mass spherical harmonics expansion has a zero dipole moment because a non-zero value would require a negative mass. So, no dipole moment for Newtonian gravity.

Higher order terms can be quite important, at least at close range. For example, the Earth's zonal quadrupole moment, J2, is one of the major perturbing factors in satellite orbits and dominates all other perturbing factors at geosynchronous satellites. Quadrupole moments only go so far. People have developed 360x360 spherical harmonics models for the Earth's gravitational field (http://cddis.nasa.gov/926/egm96/egm96.html" . JPL has developed Lunar gravity models up to degree and order 160.
 
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  • #3
I'm not talking about the Earth though I'm talking about stellar formation where you have a dust cloud which accumulates atom by atom, dust speck by dust speck to make a solar system.
 
  • #4
What difference does it make, conceptually? There is a zero dipole moment in the center of mass spherical harmonics expansion of the gravitational field for any collection of mass because there is no such thing as negative mass.

One problem with a dust cloud is that the spherical harmonics model will be time-varying, but if you want to get real picky, so is the Earth's. The Earth rotates once per day, but this problem can be addressed by developing the spherical harmonics in a rotating frame that rotates with the Earth. Even so, the Sun and Moon cause tides, which results in a daily variation in the rotating frame spherical harmonics coefficients. Mass migrates northward during winter (northern hemisphere) and southward during summer, causing an annual variation in the coefficients. Mountains rise up and erode and continents move around, causing longer term variations.

Bottom line: An extremely detailed Earth gravitational model will have time-varying spherical harmonics coefficients. The same is true for a dust cloud.
 
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  • #5
But individual atoms and molecules do experience a dipole-dipole force (the van der waals force). And I'd imagine that the magnitude of that force is either of the same order or larger then the gravitational attraction at the distances between particles of a dust cloud.
 
  • #6
NOTE: I am talking about an ELECTRONIC dipole-dipole force (from electron orbitals) not a gravitational dipole force coming from expanding the graviational force.
 
  • #7
Electric dipoles result because there is such a thing as negative charge. There is no such thing as negative mass. A similar situation occurs in magnetism, except in magnetism there is no monopole moment rather than no dipole moment.
 
  • #8
Ah, I see. You *are* talking about electric dipoles. Van der Waal forces occur at the molecular level. Astronomers don't even come close to modeling such short distances. The particles are deemed to have collided when the distance approaches some non-zero limit that is much greater than intermolecular distances. They do their modeling using doubles or floats, not extended precision numbers. Intermolecular distances and interplanetary distances don't mix well in the numerical representations used in simulations.
 
  • #9
I just remember in my undergrad astro courses iit being taught how accretion disks form and how mass accumulates and then when particles start being ejected from the accretion disk plane by random thermal fluctuations you start to see spherical masses and we calculated approximate thresholds for when this kind of activity would occur all assuming the primary force involved in holding these masses cohesive was gravity when really, it seems to me, the most important factor would be van der waals forces.

Especially since, I remember there being a problem explaining the angular momentum a solar system has and one of the possible explanations was solar winds but the solar winds would also excite the particles which would further increase the importance of electronic intermolecular forces by introducing coulombic forces as ions are formed. But never once do I remember us actually talking about the role that electronic forces play in solar system and stellar formation.
 
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FAQ: Accumulation of Mass in Stellar Formation?

What is the process of stellar formation?

The process of stellar formation is when a dense cloud of gas and dust, called a nebula, collapses under its own gravity. As the cloud collapses, it heats up and forms a protostar. The protostar continues to grow as more material is accumulated, and eventually, nuclear fusion ignites in its core, forming a star.

How does mass accumulate during stellar formation?

Mass accumulates during stellar formation through the process of accretion. As the cloud of gas and dust collapses, it forms a disk around the protostar. The material in this disk gradually falls onto the protostar, increasing its mass. This process continues until the star reaches a stable state and stops accumulating mass.

What factors influence the rate of mass accumulation in stellar formation?

The rate of mass accumulation in stellar formation is influenced by several factors, including the size and density of the initial nebula, the temperature and composition of the gas and dust, and the strength of the magnetic fields in the nebula. These factors can vary from star to star, resulting in different rates of mass accumulation.

Can the accumulation of mass in stellar formation be observed?

Yes, the accumulation of mass in stellar formation can be observed through telescopes. Astronomers can study the structure and dynamics of nebulae, as well as the properties of young stars, to understand the process of mass accumulation in stellar formation.

How does the accumulation of mass affect the properties of a star?

The accumulation of mass affects the properties of a star in several ways. The more mass a star has, the hotter and brighter it will be. It also determines the type of star it will become, with higher mass stars evolving into more massive and luminous stars. The amount of mass also affects the lifespan of a star, with more massive stars having shorter lifetimes due to their higher energy output.

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