- #1
mirandab17
- 40
- 0
If someone could also clarify how to go about this one.
Does the wrench added make it a parallel circuit?
I found the voltage of the initial circuit by simply doing V = IR = (3)(10) = 30 V.
The current flowing through the 4 ohm resistor must be the same as before... so the current for that is still 3.0 A?
Help please :s
Does the wrench added make it a parallel circuit?
I found the voltage of the initial circuit by simply doing V = IR = (3)(10) = 30 V.
The current flowing through the 4 ohm resistor must be the same as before... so the current for that is still 3.0 A?
Help please :s