- #1
Christina-
- 11
- 0
Here is what I have:
[tex]BrO_{3}^{-} + NH_{3}OH^{+} + H_{2}O --> Br^{-} + NO_{3}^{-} + 2H_{3}O^{+}[/tex]
I'm adding back spectator ions, K+ and Cl-.
[tex]KBrO_{3} + NH_{3}OHCl + H_{2}O --> KBr + KNO_{3} + 2H_{3}O^{+} + HCl[/tex]
As you can see I have 1 K and 1 Cl on the left, but 2 K and 1 Cl on the right. And because I was required to add HCl, another hydrogen has been added (unbalancing the equation).
How would I go about solving this problem? Would I add more hydrogen to the left side? And what would I do about the unbalanced # of K's?
[tex]BrO_{3}^{-} + NH_{3}OH^{+} + H_{2}O --> Br^{-} + NO_{3}^{-} + 2H_{3}O^{+}[/tex]
I'm adding back spectator ions, K+ and Cl-.
[tex]KBrO_{3} + NH_{3}OHCl + H_{2}O --> KBr + KNO_{3} + 2H_{3}O^{+} + HCl[/tex]
As you can see I have 1 K and 1 Cl on the left, but 2 K and 1 Cl on the right. And because I was required to add HCl, another hydrogen has been added (unbalancing the equation).
How would I go about solving this problem? Would I add more hydrogen to the left side? And what would I do about the unbalanced # of K's?
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