- #1
gerald V
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- TL;DR Summary
- Is the velocity resulting from the cosmic expansion simply to be added to relative velocities?
The expansion equation of the universe be ##\dot{R} = f(R)##. There shall be a photon at distance ##x## from us moving directly towards us along the line of sight. Are the velocities to be simply added, so the photon has speed ##f(x) -1## relative to us (local velocity of light set unity)? This appears as plausible to me, since then the horizon would be where ##f(R) = 1##, that is the photon stands still relative to us.
Now there shall be a reference object at a distance ##x## perfectly comoving with the cosmic dynamics, so it has velocity ##f(x)## relative to us (the gravitational influence of that object shall be negligible). If another object is at the same location as the reference object, but has velocity ##v## in the rest frame of the reference object in the lign of sight away from or towards us, what is the velocity of those object relative to us? Is it simply ##f(x) \pm v##, the relative sign dependent on the direction of the relative motion?
As always, please forgive me if my questions are dumb or I made errors. Thank you in advance for any answer.
Now there shall be a reference object at a distance ##x## perfectly comoving with the cosmic dynamics, so it has velocity ##f(x)## relative to us (the gravitational influence of that object shall be negligible). If another object is at the same location as the reference object, but has velocity ##v## in the rest frame of the reference object in the lign of sight away from or towards us, what is the velocity of those object relative to us? Is it simply ##f(x) \pm v##, the relative sign dependent on the direction of the relative motion?
As always, please forgive me if my questions are dumb or I made errors. Thank you in advance for any answer.