- #1
Vegeta
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All the places I've searched I find that the change in the internal energy for the adiabtic process is
[tex] dU = C_V\,dT [/tex]
But I don't understand why they use C_V, neither the volume nor the preassure is constant during the adiabtic process.. I know that
[tex] dU = C_V\,dT = C_p\,dT - p\,dV [/tex]
But why can that expression for dU be used for the internal energy. In the book "Physics for Scientists and Engineers", they say that because U is only a function of temperatur, then
[tex] U(T)=\int_0^{T} C_V\,dT [/tex]
Without explaining why.. I hope someone can explain this. Thx in advance.
[tex] dU = C_V\,dT [/tex]
But I don't understand why they use C_V, neither the volume nor the preassure is constant during the adiabtic process.. I know that
[tex] dU = C_V\,dT = C_p\,dT - p\,dV [/tex]
But why can that expression for dU be used for the internal energy. In the book "Physics for Scientists and Engineers", they say that because U is only a function of temperatur, then
[tex] U(T)=\int_0^{T} C_V\,dT [/tex]
Without explaining why.. I hope someone can explain this. Thx in advance.