Adiabatic Process Homework: 2 moles of CO Gas

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In summary, the conversation discusses the change in internal energy of 2 moles of Carbon monoxide gas when compressed adiabatically from 30 liters to 1/3 of its volume, assuming it can be treated as ideal. The equations used include PV^γ=constant and W=nC_v dT=nR/(γ-1)(T_2-T_1). The attempt at a solution provides a calculation using these equations, resulting in a value of -5032.41775J, which is close to the provided answer of -5100J. However, further clarification is needed to identify any potential mistakes in the calculations.
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Homework Statement



2 moles of Carbon monoxide gas start at a pressure of 1.2 atm and a volume of 30 litres. The gas is then compressed adiabatically to 1/3 this volume. Assume that the gas may be treated as ideal. What is the change in the internal energy of the gas? Does the internal energy increase or decrease? Does the temperature increase or decrease?

Homework Equations



PV^γ=constant

W=nC_v dT=nR/(γ-1)(T_2-T_1)

The Attempt at a Solution



The equation for the work done can be re-arranged to give:

(P_1 V_1-P_2 V_2)/(γ-1)

Then, using the equation that PV^γ=constant,

This equation can be "complified" to give:
(P_1 V_1)/(γ-1)[1-〖(V_1/V_2 )〗^(γ-1)

Substituting the values gives: -5032.41775J

The answer given at the back is -5100J.
Can someone please help identify where I went wrong?
Thanks!
 
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  • #2
Substituting the values gives: -5032.41775J

The answer given at the back is -5100J.
That seems pretty close, but I haven't checked the formulas. It could be rounding matter somewhere, but there are not values to check.
 
  • #3


Your approach and equations are correct. The difference in the answer could be due to rounding errors or different values used for the gas constant (R) and the specific heat at constant volume (Cv). It is also possible that the answer given in the back is an approximation and not an exact value. It is important to note that in an adiabatic process, the internal energy remains constant, so the change in internal energy is zero. The temperature, however, does change as the gas is compressed.
 

FAQ: Adiabatic Process Homework: 2 moles of CO Gas

What is an adiabatic process?

An adiabatic process is a thermodynamic process in which there is no exchange of heat between the system and its surroundings. This means that the system is completely isolated and there is no transfer of energy in the form of heat.

How is the adiabatic process different from the isothermal process?

The biggest difference between the adiabatic and isothermal process is that in an isothermal process, the temperature remains constant, while in an adiabatic process, the temperature may change. Additionally, the isothermal process allows for heat exchange with the surroundings, while the adiabatic process does not.

How do you calculate the work done in an adiabatic process?

The work done in an adiabatic process can be calculated using the formula W = -PΔV, where W is the work done, P is the pressure, and ΔV is the change in volume.

Can you provide an example of an adiabatic process?

One example of an adiabatic process is the compression of a gas in a piston-cylinder system. As the gas is compressed, the temperature increases due to the work done on the gas, but there is no heat exchange with the surroundings.

How does the adiabatic process affect the internal energy of a system?

In an adiabatic process, the internal energy of the system remains constant. This is because there is no heat exchange, so the energy within the system cannot change. This is known as the first law of thermodynamics.

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