- #1
hihiip201
- 170
- 0
Hi :
lets examine the following scenario
1.
M --------- o where M is a mass, o is a pulley with it's outter radius r attached to a mass by the belt drive -------. frictionless.
2.
M ---------O same setup but the radius is now bigger, R.
I was reading somewhere saying, a smaller pulley can move things quicker, so i decided to derive this to see for myself.
the following is the result:
for case 1:
alpha = T/(J+Mr^2)
case 2:
alpha = T/(J+MR^2)
in other word, for the same torque generated from DC motor, alpha is higher for case 1.
also, in the case where the pulley rotates at a constant velocity, constant torque output, case 1 amplify the force on the mass M where as the force on the Mass M in case 2 would be lower.
so my question is, why would anyone choose case 2 at all? what advantage does it have on any applications?
thanks
lets examine the following scenario
1.
M --------- o where M is a mass, o is a pulley with it's outter radius r attached to a mass by the belt drive -------. frictionless.
2.
M ---------O same setup but the radius is now bigger, R.
I was reading somewhere saying, a smaller pulley can move things quicker, so i decided to derive this to see for myself.
the following is the result:
for case 1:
alpha = T/(J+Mr^2)
case 2:
alpha = T/(J+MR^2)
in other word, for the same torque generated from DC motor, alpha is higher for case 1.
also, in the case where the pulley rotates at a constant velocity, constant torque output, case 1 amplify the force on the mass M where as the force on the Mass M in case 2 would be lower.
so my question is, why would anyone choose case 2 at all? what advantage does it have on any applications?
thanks