- #1
coyote_001
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I was reading an article about the Aharonov - Bohm effect and gauge invariance ( J. Phys. A: Math. Gen. 16 (1983) 2173-2177 ) and there is something I really don't get it.
The facts are:
The problem is the familiar Aharonov-Bohm one, in which we have a cylinder and inside the cylinder [tex]\rho < R[/tex] there is a magnetic field [tex]\vec{B} = B \hat{e}_z[/tex].
The writers wanted to use a different gauge (than the usual written in books) which is, in cylindrical coordinates [tex](\rho, \phi, z)[/tex],
[tex]A_{\rho} = - \rho B_z \phi[/tex]
At this gauge the vector potential [tex]\vec{A}[/tex] vanishes when [tex]\vec{B}[/tex] does, i.e. when [tex]\rho > R[/tex].
Furthermore the vector potential is a multivalued function.
The writer in order to "fix" this problem cuts the space and considers the space as a union of two regions:
[tex]0 < \phi < 2 \pi[/tex] and [tex]-\pi < \phi < \pi[/tex]
He defines in these regions two different potentials
[tex]A_{\rho}^1 = - \rho B_z \phi ,\ \ \ 0 < \phi < 2\pi[/tex], and
[tex]A_{\rho}^2 = - \rho B_z \phi' ,\ \ \ -\pi < \phi' < \pi[/tex].
Ok here is my question...
How can I calculate the correct Flux for a curve [tex]C[/tex] for [tex]\rho > R[/tex] ?
i.e. [tex]\Phi = \int \vev{A} \cdot dl[/tex] which must be [tex]\Phi = \pi R^2 B_z[/tex].
The facts are:
The problem is the familiar Aharonov-Bohm one, in which we have a cylinder and inside the cylinder [tex]\rho < R[/tex] there is a magnetic field [tex]\vec{B} = B \hat{e}_z[/tex].
The writers wanted to use a different gauge (than the usual written in books) which is, in cylindrical coordinates [tex](\rho, \phi, z)[/tex],
[tex]A_{\rho} = - \rho B_z \phi[/tex]
At this gauge the vector potential [tex]\vec{A}[/tex] vanishes when [tex]\vec{B}[/tex] does, i.e. when [tex]\rho > R[/tex].
Furthermore the vector potential is a multivalued function.
The writer in order to "fix" this problem cuts the space and considers the space as a union of two regions:
[tex]0 < \phi < 2 \pi[/tex] and [tex]-\pi < \phi < \pi[/tex]
He defines in these regions two different potentials
[tex]A_{\rho}^1 = - \rho B_z \phi ,\ \ \ 0 < \phi < 2\pi[/tex], and
[tex]A_{\rho}^2 = - \rho B_z \phi' ,\ \ \ -\pi < \phi' < \pi[/tex].
Ok here is my question...
How can I calculate the correct Flux for a curve [tex]C[/tex] for [tex]\rho > R[/tex] ?
i.e. [tex]\Phi = \int \vev{A} \cdot dl[/tex] which must be [tex]\Phi = \pi R^2 B_z[/tex].