Air Drag & No Drag on a Ball Projected Vertically

[AdityaDev]

< Moderator Note -- thread moved from General Physics to Homework Help forum >

If a ball is projected vertically upwards say with a velocity V.

Case 1: Without air drag
Case 2: With air drag

What will be the difference in v-t graphs and the motion of the ball
Air drag D=bv (b is a constant,v is velocity)

I know that in case 1, the velocity decreases as the ball goes up from V to 0.
$v=V-gt$
$(y=-mx+c)$
Hence it will be a straight line with slope -g.
With air drag will the graph still be a straight line??

 

[PeroK]

< Moderator Note -- thread moved from General Physics to Homework Help forum >

If a ball is projected vertically upwards say with a velocity V.

Case 1: Without air drag
Case 2: With air drag

What will be the difference in v-t graphs and the motion of the ball
Air drag D=bv (b is a constant,v is velocity)

I know that in case 1, the velocity decreases as the ball goes up from V to 0.
$v=V-gt$
$(y=-mx+c)$
Hence it will be a straight line with slope -g.
With air drag will the graph still be a straight line??

What does the slope of the v-t graph represent? And when is this graph a straight line?

 

[AdityaDev]

What does the slope of the v-t graph represent? And when is this graph a straight line?

it is a straight line.. for consrant acceleration, vt graph is a straight line which is inclined... v=-gt+V is a straight line. pls don't say its parabolic.

 

[PeroK]

And is there constant acceleration with air drag?

 

[AdityaDev]

And is there constant acceleration with air drag?

i got the answer...i was talking about no air drag case...with air drag, after serious integration, i found v(t) and it is a function with exponent and is in terms of terminal velocity...you can close the thread.